php – 两个错误 – 在自定义管理面板上标记按钮附带的项目

在preorder.php页面上连接到另一个(它自己的)数据库,在用户填写表单和条带处理订单后,我检查收费是否像这样支付;

if ($charge->paid == true) {
    $amountReadable = $amount / 100; // to add in decimal points
    echo '<div class="alert alert-success">Your card was successfully billed for $'.$amountReadable.'</div>';
    $status = "paid";

然后我连接到主数据库和管理数据库(它们都有’orders’表)并插入此查询：

$connect = mysql_connect("localhost",DB_USER,DB_PASS);
 if (!$connect){
 die('Could not connect: ' . mysql_error());
 }

 mysql_select_db(DB_NAME,$connect);

 $query = "INSERT INTO 'DB_NAME'.`orders` (`email`,`name`,`qty`,`product`,`amount`,`stripe_customer_id`,`stripe_charge_id`,`address1`,`address2`,`city`,`state`,`zip`,`timestamp`,`status`) VALUES ('$email','$cardName','$qty','$product','$amountReadable','$customer->id','$charge->id','$cardAddress1','$cardAddress2','$cardCity','$cardState','$cardZipcode',CURRENT_TIMESTAMP`,$status);";

 mysql_query($query);

 if (mysql_errno()) {
 $error = "MySQL error ".mysql_errno().": ".mysql_error()."n<br>When executing:<br>n$queryn<br>";
 exit;   
 }
 mysql_close($connect);

 //insert into db for admin
 $connect = mysql_connect("--------","------","-------");
 if (!$connect){
 die('Could not connect: ' . mysql_error());
 }

 mysql_select_db(database2,$connect);

 $query = "INSERT INTO 'database2'.`orders` (`email`,CURRENT_TIMESTAMP,$status);";

然后在具有自己的数据库(上面的数据库2)的管理面板上,(orders.php)我将这些数据拉入这样的引导表中：

编辑1#：我将管理面板中的orders.php更改为：

$result = mysqli_query($con,"SELECT * FROM orders");

echo "<table border='1' data-toggle='table'>
<tr>
<th>id</th>
<th>email</th>
<th>name</th>
<th>qty</th>
<th>product</th>
<th>amount</th>
<th>address1</th>
<th>address2</th>
<th>city</th>
<th>state</th>
<th>zip</th>
<th>status</th>
</tr>";

 while($row = mysqli_fetch_array($result))
 {
 echo "<tr>";
  echo "<td>" . $row['id'] . "</td>";
  echo "<td>" . $row['email'] . "</td>";
  echo "<td>" . $row['name'] . "</td>";
  echo "<td>" . $row['qty'] . "</td>";
  echo "<td>" . $row['product'] . "</td>";
  echo "<td>" . $row['amount'] . "</td>";
  echo "<td>" . $row['address1'] . "</td>";
  echo "<td>" . $row['address2'] . "</td>";
  echo "<td>" . $row['city'] . "</td>";
  echo "<td>" . $row['state'] . "</td>";
  echo "<td>" . $row['zip'] . "</td>";
  echo "<td>" . $row['status']. "</td>";
  echo "<td><form action='markshipped.php' method='POST'><input type='hidden' name='status' value='".$row["id"]."'/><input type='submit' name='submit-btn' value='Mark Item Shipped' /><form></td>";
  echo "</tr>";
 }
echo "</table>";

那么我的markshipped.php是：

<?php
$con=mysqli_connect("----","----","----");
// Check connection
if (mysqli_connect_errno()) {
  echo "Failed to connect to MySQL: " . mysqli_connect_error();
}

mysqli_query($con,"UPDATE orders SET status='shipped' WHERE id=$id");

mysqli_close($con);
?>

我仍然不太熟悉php / mysql,不幸的是我无法测试它,直到有人购买任何东西,因为条纹测试模式没有一张卡片无法通过表格…

所以我的问题主要是：

我有两个错误说：

1.未定义变量：第9行/admin/orders/markshipped.php中的id

– 这是这一行：mysqli_query($con,“UPDATE命令SET status =’shipping’WHERE id = $id”);

2.未定义的索引：第88行的/admin/orders/orders.php中的状态

– 这是：echo“< td>” . $行[“状态”. “< / TD>” 中;

显然我设置$status =“付费”;错误和/或错误的地方.

如何正确设置这些项目以便能够将项目标记为“已付款”,然后在单击每行上的“标记项目已发送”按钮后将其更改为“已发货”？你能发现我的代码中的任何其他错误吗？

非常感谢你的时间！