php – 使用一个按钮提交多个表单并在MySQL中存储变量
发布时间:2020-12-13 16:49:38 所属栏目:PHP教程 来源:网络整理
导读:我目前正在学习表单和Ajax发布,没有页面刷新.我有树形式和一个提交按钮.我已经为每个输入字段分配了php变量,它将获取所输入内容的值.每个输入框都会回显该值.是否可以同时提交所有三个表格?如果是,在点击按钮后如何将这些值提交到 MySQL数据库? 阿贾克斯:
我目前正在学习表单和Ajax发布,没有页面刷新.我有树形式和一个提交按钮.我已经为每个输入字段分配了php变量,它将获取所输入内容的值.每个输入框都会回显该值.是否可以同时提交所有三个表格?如果是,在点击按钮后如何将这些值提交到
MySQL数据库?
阿贾克斯: function() { $.ajax({ type: "POST",url: "posting.php",data: { "name": $("#name").val(),"age": $("#age").val(),"phone": $("#phone").val(),"email": $("#email").val(),"job": $("#job").val(),"hobby": $("#hobby").val(),},success: function(data) { $("#inputResult").html(data); } }); } PHP if ($_SERVER['REQUEST_METHOD'] == 'POST') { if (isset($_POST['name'])) { $name = $_POST['name']; echo '<div id="name_input"><h2 class="lastTab">Name:</h2>' . $name . '</div>'; } if (isset($_POST['age'])) { $age = $_POST['age']; echo '<div id="age_input"><h2 class="lastTab">Age:</h2>' . $age . '</div>'; } if (isset($_POST['phone'])) { $phone = $_POST['phone']; echo '<div id="phone_input"><h2 class="lastTab">Phone:</h2>' . $phone . '</div>'; } if (isset($_POST['email'])) { $email = $_POST['email']; echo '<div id="email_input"><h2 class="lastTab">Email:</h2>' . $email . '</div>'; } if (isset($_POST['job'])) { $job = $_POST['job']; echo '<div id="job_input"><h2 class="lastTab">Job:</h2>' . $job . '</div>'; } if (isset($_POST['hobby'])) { $hobby = $_POST['hobby']; echo '<div id="hobby_input"><h2 class="lastTab">Hobby:</h2>' . $hobby . '</div>'; } } HTML <div id="tab-1" class="ui-tabs-panel ui-tabs-hide"> <form autocomplete="off" method="post" enctype="multipart/form-data" id="postForm1" name="postForm1" class="postForm"> Name <input type="text" id="name" class="detail" name="name" value="" /> Age <input type="text" id="age" class="detail" name="age" value="" /> </form> </div>. <div id="tab-2" class="ui-tabs-panel ui-tabs-hide"> <form autocomplete="off" method="post" enctype="multipart/form-data" id="postForm2" name="postForm2" class="postForm"> Phone Number <input type="text" id="phone" class="detail" name="phone" value="" /> Email <input type="text" id="email" class="detail" name="email" value="" /> </form> </div> <div id="tab-3" class="ui-tabs-panel ui-tabs-hide"> <form autocomplete="off" method="post" enctype="multipart/form-data" id="postForm3" name="postForm3" class="postForm"> Job <input type="text" id="job" class="detail" name="job" value="" /> Hobby <input type="text" id="hobby" class="detail" name="hobby" value="" /> </form> </div> 解决方法
您可以使用javascript来捕获表单的提交,也可以触发您创建的功能.对于第二种情况,它不必是3种形式甚至是形式元素
HTML: <div id="tab-1" class="ui-tabs-panel ui-tabs-hide"> <form autocomplete="off" method="post" enctype="multipart/form-data" id="postForm1" name="postForm1" class="postForm"> Name <input type="text" id="name" class="detail" name="name" value="" /> Age <input type="text" id="age" class="detail" name="age" value="" /> </form> </div>. <div id="tab-2" class="ui-tabs-panel ui-tabs-hide"> <form autocomplete="off" method="post" enctype="multipart/form-data" id="postForm2" name="postForm2" class="postForm"> Phone Number <input type="text" id="phone" class="detail" name="phone" value="" /> Email <input type="text" id="email" class="detail" name="email" value="" /> </form> </div> <div id="tab-3" class="ui-tabs-panel ui-tabs-hide"> <form autocomplete="off" method="post" enctype="multipart/form-data" id="postForm3" name="postForm3" class="postForm"> Job <input type="text" id="job" class="detail" name="job" value="" /> Hobby <input type="text" id="hobby" class="detail" name="hobby" value="" /> <input type="button" value="SAVE" onclick="saveThem()" /> </form> </div> AJAX: function saveThem() { var name = $.trim($("#name").val()); var age = $.trim($("#age").val()); var phone = $.trim($("#phone").val()); var email = $.trim($("#email").val()); var job = $.trim($("#job").val()); var hobby = $.trim($("#hobby").val()); var dataString = 'name='+name+'&age='+age+'&phone='+phone+'&email='+email+'&job='+job+'&hobby='+hobby; $.ajax({ type: "POST",url: 'http://www.yourdomain.com/something.php',data: dataString,dataType: "json",success: function(data) { if(data.response){ alert(data.message); } $("#inputResult").html(data); } }); } something.php //Get posted variables $name = (isset($_POST['name'])) ? strip_tags($_POST['name']) : NULL; $age = (isset($_POST['age'])) ? strip_tags($_POST['age']) : NULL; $phone = (isset($_POST['phone'])) ? strip_tags($_POST['phone']) : NULL; $email = (isset($_POST['email'])) ? strip_tags($_POST['email']) : NULL; $job = (isset($_POST['job'])) ? strip_tags($_POST['job']) : NULL; $hobby = (isset($_POST['hobby'])) ? strip_tags($_POST['hobby']) : NULL; //execute your query $sql = "INSERT INTO ..."; //Return results back to ajax $result = array( 'response' => 1,'message' => 'We have a success!' ); echo json_encode($result); 所以总结与使用PHP几乎相同,但在中间有一些JavaScript. 编辑:使用jQuery serialize() $('form').submit(function() { $dataString = $(this).serialize(); //This will produce the same result,based on input names }); (编辑:李大同) 【声明】本站内容均来自网络,其相关言论仅代表作者个人观点,不代表本站立场。若无意侵犯到您的权利,请及时与联系站长删除相关内容! |