php – 有没有办法在preg_replace_callback回调函数中传递另一个

让我们来看看这个例子(这只是一个例子！)的代码：

class Something(){
    public function Lower($string){
        return strtolower($string);
    }
}
class Foo{
    public $something;
    public $reg;
    public $string;
    public function __construct($reg,$string,$something){
        $this->something = $something;
        $this->reg = $reg;
        $this->string = $string;
    }
    public function Replace(){
        return preg_replace_callback($this->reg,'Foo::Bar',$this->string);
    }
    public static function Bar($matches){
        /*
        * [...]
        * do something with $matches and create the $output variable
        * [...]
        */

        /*
        * I know is really useless in this example,but i need to have an istance to an object here
        * (in this example,the Something object,but can be something else!)
        */
        return $this->something->Lower($output);
    }
}
$s = new Something();
$foo = new Foo($myregexp,$mystring,$s);
$content = $foo->Replace();

所以,php手册说,在preg_replace_callback()中使用类方法作为回调,该方法必须是抽象的.

我需要在回调函数中传递一个previuosly已初始化的对象(在该示例中为Something类的一个实例)的实例.

我尝试使用call_user_func(),但没有工作(因为我以这种方式我错过了match参数).

有没有办法做到这一点,还是让我分开进程(在preg_match_all之前,为每个匹配检索替换值,然后是一个简单的preg_replace)？

编辑：作为旁注,在tom haigh答案之前,我使用这个工作(在这个例子中,这是替换方法)：

$has_dynamic = preg_match_all($this->reg,$this->string,$dynamic);
if($has_dynamic){
    /*
    * The 'usefull' subset of my regexp is the third,so $dynamic[2]
    */
    foreach($dynamic[2] AS $key => $value){
        $dynamic['replaces'][$key] = $this->Bar($value);
    }
    /*
    * ..but i need to replace the complete subset,so $dynamic[0]
    */
    return str_replace($dynamic[0],$dynamic['replaces'],$this->string);
}else{
    return $this->string;
}

希望可以帮助某人.