如何打开文本文件并写入它附加样式与PHP？

发布时间：2020-12-13 16:25:20 所属栏目：PHP教程来源：网络整理

导读：如何打开一个文本文件并用php appendstyle写入它 textFile.txt //caught these variables $var1 = $_POST['string1']; $var2 = $_POST['string2']; $var3 = $_POST['string3']; $handle = fopen("textFile.txt","w"); fwrite = ("%s %s %sn",$var1,$var2,$v

如何打开一个文本文件并用php appendstyle写入它

textFile.txt

        //caught these variables
        $var1 = $_POST['string1'];
        $var2 = $_POST['string2'];
        $var3 = $_POST['string3'];

    $handle = fopen("textFile.txt","w");
    fwrite = ("%s %s %sn",$var1,$var2,$var3,handle);//not the way to append to textfile
fclose($handle);

要将数据附加到文件中,您需要以附加模式打开文件(请参阅 fopen)：

‘a’
Open for writing only; place the file pointer at the end of the file. If the file does not exist,attempt to create it.

‘a+’
Open for reading and writing; place the file pointer at the end of the file. If the file does not exist,attempt to create it.

所以在只写append模式下打开textFile.txt：

fopen("textFile.txt","a")

但您也可以使用将fopen,fwrite和fclose组合在一起的更简单的功能file_put_contents：

$data = sprintf("%s %s %sn",$var3);
file_put_contents('textFile.txt',$data,FILE_APPEND);

（编辑：李大同）

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