php – Youtube API(无效请求)有什么问题？

但！

当我上传任何“图像”而不是“视频”时,它会返回状态“200”和视频ID.

为什么我无法上传视频？

$eq = 'accountType=HOSTED_OR_GOOGLE&Email='.$YOUTUBE_EMAIL.'&Passwd='.$YOUTUBE_PASS.'&service=youtube&source='.$API_NAME;
if ($fp = fsockopen ("ssl://www.google.com",443,$errno,$errstr,20))
{
    $request ="POST /youtube/accounts/ClientLogin HTTP/1.0rn";
    $request.="Host: www.google.comrn";
    $request.="Content-Type:application/x-www-form-urlencodedrn";
    $request.="Content-Length: ".strlen($eq)."rn";
    $request.="rnrn";
    $request.=$eq;
    fwrite($fp,$request,strlen($request));

    while (!feof($fp))
    $response.=fread($fp,8192);
    //fclose($fp);
}

preg_match("!(.*?)Auth=(.*?)n!si",$response,$ok);
$AUTH_TOKEN = $ok[2];

$data = "<?xml version='1.0'?>
<entry xmlns='http://www.w3.org/2005/Atom'xmlns:media='http://search.yahoo.com/mrss/' xmlns:yt='http://gdata.youtube.com/schemas/2007'>
    <media:group>
     <media:title type='plain'>test</media:title>
     <media:description type='plain'>test</media:description>
     <media:category scheme='http://gdata.youtube.com/schema /2007/categories.cat'>People</media:category>
     <media:keywords>toast,wedding</media:keywords>
    </media:group>
</entry> ";

if ($fp = fsockopen ("gdata.youtube.com",80,20))
{
    $request ="POST /action/GetUploadToken HTTP/1.1rn";
    $request.="Host: gdata.youtube.comrn";
    $request.="Content-Type: application/atom+xml; charset=UTF-8rn";
    $request.="Content-Length: ".strlen($data)."rn";
    $request .="Authorization: GoogleLogin auth=".$AUTH_TOKEN."rn";
    $request.="X-GData-Client: ".$API_NAME." rn";
    $request.="X-GData-Key: key=".$API_KEY." rn";
    $request.="rn";
    $request.=$data."rn";

    socket_set_timeout($fp,10);
    fputs($fp,strlen($request));
    $response = fread($fp,3280);
    fclose($fp);
}


preg_match('|<url>(.*)</url>|Uis',$url);
preg_match('|<token>(.*)</token>|Uis',$token);

print "
    <form action='".$url[1]."?nexturl=http%3A%2F%2Fwww.google.com' method='post' enctype='multipart/form-data'>
      <input type='file' name='file'>
      <input type='hidden' name='token' value='".$token[1]."'>
      <input type='submit' value='go'>
    </form> ";