PHP：如何从数组中动态输入选项卡中的值？

<?php 

    $options = array(

        array("name" => "Title","desc" => "Description","type" => '_one',"tab-name" => "Tab 1"

        ),array("name" => "Title2","desc" => "Description2","type" => '_two',"tab-name" => "Tab 2"

        ),array("name" => "Title3","desc" => "Description3","type" => '_three',"tab-name" => "Tab 3"

        )

    )

?>

我已经做了一个函数来回显出名称,desc,这是完美的

这里是：

<?php

function create_heading($value) {
    echo '<h2>'.$value['name'].'</h2>';
}
function create_description($value){
    echo '<p>'.$value['desc'].'</p>'
}

function wrapper1($value) {
    echo '<h1>This is the wrapper 1</h1>'
    create_heading($value);
    create_description($value);
}

function wrapper2($value) {
    echo '<h1>This is the wrapper 2</h1>'
    create_heading($value);
    create_description($value);
}

function wrapper2($value) {
    echo '<h1>This is the wrapper 3</h1>'
    create_heading($value);
    create_description($value);
}


function render_things($options) {
    foreach ($options as $value) {
        switch($value['type']) {
            case "one":
                wrapper1($value);
                break;
            case "two":
                wrapper2($value);
            case "three":
                wrapper3($value);
        }
    }
}


render_things();

?>

所以有什么问题：

问题是如何根据数组中的tab-name动态回显选项卡中的这些值意味着我已经在tab-name中给出了第二个数组的值为2,所以如果我改变它应该在第二个选项卡中打印它应该分别将值打印到一个或三个.

我希望你们明白.

body {font-family: "Lato",sans-serif;}

/* Style the tab */
div.tab {
    overflow: hidden;
    border: 1px solid #ccc;
    background-color: #f1f1f1;
}

/* Style the buttons inside the tab */
div.tab button {
    background-color: inherit;
    float: left;
    border: none;
    outline: none;
    cursor: pointer;
    padding: 14px 16px;
    transition: 0.3s;
    font-size: 17px;
}

/* Change background color of buttons on hover */
div.tab button:hover {
    background-color: #ddd;
}

/* Create an active/current tablink class */
div.tab button.active {
    background-color: #ccc;
}

/* Style the tab content */
.tabcontent {
    display: none;
    padding: 6px 12px;
    border: 1px solid #ccc;
    border-top: none;
}

<div class="tab">
  <button class="tablinks" onclick="openCity(event,'tab1')" id="defaultOpen">tab 1</button>
  <button class="tablinks" onclick="openCity(event,'tab2')">tab 2</button>
  <button class="tablinks" onclick="openCity(event,'tab3')">Tab 3</button>
</div>

<div id="tab1" class="tabcontent">
  <h1>This is tab 1</h1>
</div>

<div id="tab2" class="tabcontent">
  <h1>This is tab 2</h1>
</div>

<div id="tab3" class="tabcontent">
  <h1>This is tab 3</h1>
</div>

<script>
function openCity(evt,cityName) {
    var i,tabcontent,tablinks;
    tabcontent = document.getElementsByClassName("tabcontent");
    for (i = 0; i < tabcontent.length; i++) {
        tabcontent[i].style.display = "none";
    }
    tablinks = document.getElementsByClassName("tablinks");
    for (i = 0; i < tablinks.length; i++) {
        tablinks[i].className = tablinks[i].className.replace(" active","");
    }
    document.getElementById(cityName).style.display = "block";
    evt.currentTarget.className += " active";
}

// Get the element with id="defaultOpen" and click on it
document.getElementById("defaultOpen").click();
</script>

注意：我不想使用js来实现这些信息,所以如果可以使用PHP,请尽量避免使用js答案.