如何在cakephp 3中获得最近每小时/每日/每周/每年间隔的总计数总
发布时间:2020-12-13 16:05:11 所属栏目:PHP教程 来源:网络整理
导读:我有一张桌子如下 – 现在我需要报告每小时,每周,每月和每年的总计数.它可能有0,但应该包含在结果中.例如,我需要如下结果 – $hourlyResult = array('00:01' = '5','00:02' = '9','00:03' = '50','00:04' = '5',............................'00:55' = '95',
我有一张桌子如下 –
现在我需要报告每小时,每周,每月和每年的总计数.它可能有0,但应该包含在结果中.例如,我需要如下结果 – $hourlyResult = array( '00:01' => '5','00:02' => '9','00:03' => '50','00:04' => '5',.............. .............. '00:55' => '95','00:56' => '0','00:57' => '20','00:58' => '33','00:59' => '5',); $weeklyResult = array( 'SAT' => '500','SUN' => '300' ............. ............. 'FRI' => '700' ); 如何在cakephp 3中构建查询?我得到以下链接,但不能到目前为止. GROUP BY WEEK with SQL 我做了什么 – $this->loadModel('Searches'); $searches = $this->Searches ->find('all') ->select(['created','count']) ->where('DATE(Searches.created) = DATE_SUB(CURDATE(),INTERVAL 1 DAY)') ->group(WEEK(date)) ->hydrate(false) ->toArray(); pr($searches); 解决方法
这是你如何做到的.
按年计算 $query = $this->Searches->find(); $query = $this->Searches ->find() ->select([ 'total_count' => $query->func()->sum('count'),'year' => $query->func()->year(['created' => 'literal']) ]) ->group(['year']) ->hydrate(false); 要么 $query = $this->Searches ->find() ->select(['total_count' => 'SUM(count)','year' => 'YEAR(created)']) ->group(['year']) ->hydrate(false); 按周计算 $query = $this->Searches->find(); $query = $this->Searches ->find() ->select([ 'total_count' => $query->func()->sum('count'),'day_of_week' => $query->func()->dayOfWeek('created') ]) ->group(['day_of_week']) ->hydrate(false); 要么 $query = $this->Searches ->find() ->select(['total_count' => 'SUM(count)','day_of_week' => 'DAYOFWEEK(created)']) ->group(['day_of_week']) ->hydrate(false); 以同样的方式获得按小时或月计的总和. (编辑:李大同) 【声明】本站内容均来自网络,其相关言论仅代表作者个人观点,不代表本站立场。若无意侵犯到您的权利,请及时与联系站长删除相关内容! |