php利用嵌套数组拼接与解析json的方法
利用嵌套数组 拼接混合json -包含对象数组// 自 PHP 5.4 起
$array = [ "status" => "0","message" => "ok","arr"=> [] ]; class Person { //定义一个构造方法初始化赋值 for($i=0;$i<10;$i++) //var_dump($array); echo json_encode($array); ?> php利用嵌套数组 解析混合json 包含对象数组$v) {
if(is_object($v)) $arr[$k]=json_to_array($v); //判断类型是不是object
else $arr[$k]=$v;
}
return $arr;
}
$s='{"webname":"homehf","url":"www.homehf.com","qq":"744348666"}';
//将字符转成JSON
$web=json_decode($s);
$arr=array();
foreach($web as $k=>$v)
$arr[$k]=$v;
echo "
"; print_r($arr); echo ""; $s='{"webname":"homehf","contact":{"qq":"744348666","mail":"nieweihf@163.com","xx":"xxxxxxx"}}'; ";"; /**** $mys='{"status":"0","message":"ok","arr":[{"name":"ren","age":0},{"name":"ren","age":1},"age":2},"age":3},"age":4},"age":5},"age":6},"age":7},"age":8},"age":9}]}'; $myweb=json_decode($mys); echo $myweb->status; for($i=0;$i<10;$i++) 以上就是本文的全部内容,希望对大家的学习有所帮助,也希望大家多多支持编程之家。 (编辑:李大同) 【声明】本站内容均来自网络,其相关言论仅代表作者个人观点,不代表本站立场。若无意侵犯到您的权利,请及时与联系站长删除相关内容! |