php发送post请求函数分享
发布时间:2020-12-12 20:05:41 所属栏目:PHP教程 来源:网络整理
导读:代码如下: function do_post_request($url,$data,$optional_headers = null) { $params = array('http' => array( 'method' => 'POST', 'content' => $data )); if ($optional_headers !== null) { $params['http']['header'] = $optional_headers; } $ctx =
代码如下: function do_post_request($url,$data,$optional_headers = null)
{ $params = array('http' => array( 'method' => 'POST', 'content' => $data )); if ($optional_headers !== null) { $params['http']['header'] = $optional_headers; } $ctx = stream_context_create($params); $fp = @fopen($url,'rb',false,$ctx); if (!$fp) { throw new Exception("Problem with $url,$php_errormsg"); } $response = @stream_get_contents($fp); if ($response === false) { throw new Exception("Problem reading data from $url,$php_errormsg"); } return $response; }
代码如下: //json字符串 $data = "{...}"; //转换成数组 $data=json_decode($data,true); $postdata = http_build_query($data); do_post_request("http://localhost",$postdata); (编辑:李大同) 【声明】本站内容均来自网络,其相关言论仅代表作者个人观点,不代表本站立场。若无意侵犯到您的权利,请及时与联系站长删除相关内容! |