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?1，获取字符串中分隔符分隔的长度
alter FUNCTION GetLenBySelChar
(
?-- Add the parameters for the function here
?@StrParams nvarchar(4000),
?@char char(1)=N'1'
)
RETURNS int
AS
BEGIN
?declare? ?@m? int,
?@length int
?set @length=0
?
?set? @m=CHARINDEX(@char,@strparams)?
?WHILE? @m>0?
?BEGIN?
???? set? @strparams=substring(@strparams,@m+1,datalength(@strparams)-1)?
???set @length=@length+1
???? set? @m=CHARINDEX(@char,@strparams)?
?END
?return @length
END
2,返回每个分隔的字符串
ALTER FUNCTION [dbo].[funGetSubStrBySelChar]
(
?-- Add the parameters for the function here
?@StrParams nvarchar(4000),
?@char char(1)=N'1'
)
RETURNS nvarchar(4000)
AS
BEGIN
?declare? --@str? varchar(300),
?@id? varchar(3000),
?@m? int,
?@n? int?
?--set? @str='a,b,c,d,e'?
?--set? @m=CHARINDEX(',',@str)?
?--set? @n=1?
?--WHILE? @m>0?
?--BEGIN?
?--??? set? @id=substring(@str,@n,@m-@n)?
?--??? print? @id?
?--??? set? @n=@m+1?
?--??? set? @m=CHARINDEX(',@str,@n)?
?--END
?set @m=charindex(@char,@strparams)
?set @n=1
?if @m>0
?begin
??set @id=substring(@strparams,1,@m-@n)
?end
?else
?begin
??set @id=null
?end
???return @id
END
三，返回取出分隔符后新的字符串
ALTER FUNCTION [dbo].[funGetNewStr]
(
?-- Add the parameters for the function here
?@StrParams nvarchar(4000),
?@char char(1)=N','
)
RETURNS nvarchar(4000)
AS
BEGIN
?declare? --@str? varchar(300),@strparams)
?if @m>0
?begin
?set @strparams=substring(@strparams,datalength(@strparams)-@m-1)
?end
?return @strparams
END
（编辑：李大同）
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