(转)查看SQLServer最耗资源时间的SQL语句

? ? ? ? ? 原文地址：https://www.cnblogs.com/My-Dream/p/6270308.html

1.找出执行时间最长的10条SQL（适用于SQL SERVER 2005及其以上版本）

SELECT top 10  
    (total_elapsed_time / execution_count)/1000 N‘平均时间ms‘,total_elapsed_time/1000 N‘总花费时间ms‘,total_worker_time/1000 N‘所用的CPU总时间ms‘,total_physical_reads N‘物理读取总次数‘,total_logical_reads/execution_count N‘每次逻辑读次数‘,total_logical_reads N‘逻辑读取总次数‘,total_logical_writes N‘逻辑写入总次数‘,execution_count N‘执行次数‘,creation_time N‘语句编译时间‘,last_execution_time N‘上次执行时间‘,SUBSTRING(  
        st.text,(qs.statement_start_offset/2) + 1,(  
            (CASE statement_end_offset WHEN -1 THEN DATALENGTH(st.text) ELSE qs.statement_end_offset END - qs.statement_start_offset)/2  
        ) + 1  
    ) N‘执行语句‘,qp.query_plan  
FROM  sys.dm_exec_query_stats AS qs 
CROSS APPLY sys.dm_exec_sql_text(qs.sql_handle) st 
CROSS APPLY sys.dm_exec_query_plan(qs.plan_handle) qp  
WHERE  
    SUBSTRING(  
        st.text,(  
            (CASE statement_end_offset WHEN -1 THEN DATALENGTH(st.text) ELSE qs.statement_end_offset END - qs.statement_start_offset)/2  
        ) + 1  
    ) not like ‘%fetch%‘  
ORDER BY  total_elapsed_time / execution_count DESC;  


如果想对SQL作筛选，可将
not like ‘%fetch%‘  换成  like ‘%user%‘就可以找出SQL语句中含有user关键字的SQL

?

2 找出执行最慢的SQL语句（适用于SQL SERVER 2005及其以上版本）

SELECT
    (total_elapsed_time / execution_count)/1000 N‘平均时间ms‘,SUBSTRING(st.text,((CASE statement_end_offset
    WHEN -1 THEN DATALENGTH(st.text)
    ELSE qs.statement_end_offset END
    - qs.statement_start_offset)/2) + 1) N‘执行语句‘,last_execution_time N‘上次执行时间‘
    FROM
    sys.dm_exec_query_stats AS qs CROSS APPLY sys.dm_exec_sql_text(qs.sql_handle) st
WHERE
SUBSTRING(st.text,((CASE statement_end_offset
WHEN -1 THEN DATALENGTH(st.text)
ELSE qs.statement_end_offset END
- qs.statement_start_offset)/2) + 1) not like ‘?tch%‘
ORDER BY
total_elapsed_time / execution_count DESC;

?

?3 找出最耗时的前N条T-SQL语句 ?（适用于SQL SERVER 2005及其以上版本）

--给N赋初值为30  
declare @n int set @n=30   
  
;with maco as   
(     
    select top (@n)  
        plan_handle,sum(total_worker_time) as total_worker_time,sum(execution_count) as execution_count,count(1) as sql_count  
    from sys.dm_exec_query_stats group by plan_handle  
    order by sum(total_worker_time) desc  
)  
select  t.text,a.total_worker_time,a.execution_count,a.sql_count  
from    maco a  
        cross apply sys.dm_exec_sql_text(plan_handle) t  
          
/* 结果格式如下  
text     total_worker_time  execution_count   sql_count  
-------- ------------------ ----------------- ---------  
内容略  
*/  

?

?4?平均耗CPU最多的前个SQL?（SQL SERVER 2005或以上版本）

SELECT TOP 5 total_worker_time / execution_count AS [Avg CPU Time],(qs.statement_start_offset/2)+1,((CASE qs.statement_end_offset  
            WHEN -1 THEN DATALENGTH(st.text)  
            ELSE qs.statement_end_offset  
            END - qs.statement_start_offset)/2) + 1) AS statement_text   
 FROM sys.dm_exec_query_stats AS qs   
 CROSS APPLY sys.dm_exec_sql_text(qs.sql_handle) AS st   
 ORDER BY total_worker_time/execution_count DESC  

??

5 平均耗CPU最多的前个SQL? （SQL SERVER 2008或以上版本）

SELECT TOP 20
    total_worker_time/1000 AS [总消耗CPU 时间(ms)],execution_count [运行次数],qs.total_worker_time/qs.execution_count/1000 AS [平均消耗CPU 时间(ms)],last_execution_time AS [最后一次执行时间],min_worker_time /1000 AS [最小执行时间(ms)],max_worker_time /1000 AS [最大执行时间(ms)],SUBSTRING(qt.text,qs.statement_start_offset/2+1,(CASE WHEN qs.statement_end_offset = -1 
        THEN DATALENGTH(qt.text) 
        ELSE qs.statement_end_offset END -qs.statement_start_offset)/2 + 1) 
    AS [使用CPU的语法],qt.text [完整语法],qt.dbid,dbname=db_name(qt.dbid),qt.objectid,object_name(qt.objectid,qt.dbid) ObjectName
FROM sys.dm_exec_query_stats qs WITH(nolock)
CROSS apply sys.dm_exec_sql_text(qs.sql_handle) AS qt
WHERE  execution_count>1
ORDER BY (qs.total_worker_time/qs.execution_count/1000) DESC

?

6 总耗CPU最多的前个SQL?（SQL SERVER 2008或以上版本）

SELECT TOP 20
    total_worker_time/1000 AS [总消耗CPU 时间(ms)],qt.dbid) ObjectName
FROM sys.dm_exec_query_stats qs WITH(nolock)
CROSS apply sys.dm_exec_sql_text(qs.sql_handle) AS qt
WHERE execution_count>1
ORDER BY  total_worker_time DESC

（编辑：李大同）

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