sqlserver查询连续签到天数

create table #t
(keyId int identity,actionDate datetime)
insert into #t(actionDate) select distinct CreateDate from CRM_ScoreTransaction WHERE MemberID=‘1E7DFF7F-51ED-4E21-8471-E892E0326BBD‘ order BY CreateDate desc
---采用遍历的方式生成用户连续签到的天数 start
declare @i int,@imax int,@startDate datetime
set @i=1
select @imax = max(keyId),@startDate =max(actionDate) from #t

while @i <@imax
begin
set @startDate = dateadd(day,-1,@startDate)
set @i [email?protected]+1

if not exists(
select null from #t where keyId [email?protected] and actionDate [email?protected]
)
begin
set @[email?protected]
break;
end
end

if @imax is null
begin
set @i=0
end

select convert(varchar(20),@i) signinday

---采用遍历的方式生成用户连续签到的天数 end gotruncate table #tdrop table #t

（编辑：李大同）

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