通过区域坐标获取sqlserver中的geometry 的区域范围内的坐标

sqlserver目前已经可以支持地理空间字段了，也就是 geometry?

API地址:

http://msdn.microsoft.com/zh-cn/LIBRARY/cc280487.aspx

创建表和geometry字段以及插入点，线，多边形的sql如下:

IF OBJECT_ID ( 'dbo.SpatialTable','U' ) IS NOT NULL 
    DROP TABLE dbo.SpatialTable;
GO

CREATE TABLE SpatialTable 
    ( id int IDENTITY (1,1),geom geometry,adress varchar );
GO

INSERT INTO SpatialTable (geom)
VALUES (geometry::STGeomFromText('POINT (20 180)',4326));

INSERT INTO SpatialTable (geom)
VALUES (geometry::STGeomFromText('LINESTRING (100 100,20 180,180 180)',4326));

INSERT INTO SpatialTable (geom)
VALUES (geometry::STGeomFromText('POLYGON ((0 0,150 0,150 150,0 150,0 0))',4326));
GO

ps: 4326是空间引用标识符 (SRID)? ? 一般写0或者4326

存入表中的geom字段如下:

查询语句

假如我们在数据库中存了很多坐标点的地址?

选取圆形区域范围的 地址---也就是 圆心到半径范围内的所有点

DECLARE @g geometry;
set @g = geometry::STGeomFromText('POINT(104.12765 30.60445)',4326)
SELECT address,geom.STY,geom.STX from SpatialTable  where geom.STDistance(@g)<=0.005

PS：这里diatance的单位是 英里

选取多边形

DECLARE @g geometry;
set @g = geometry::STGeomFromText('POLYGON ((104.12189573049204 30.608145728994504,104.12223905324595 30.60282680842528,104.13262456655161 30.603122311674902,104.13176625966685 30.610066378528995,104.12189573049204 30.608145728994504,104.12189573049204 30.608145728994504))',4326)
SELECT address  from  SpatialTable
where    geom.STIntersects(@g)=1

（编辑：李大同）

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