SQLServer存储过程实现单条件分页
发布时间：2020-12-12 09:12:58 所属栏目：MsSql教程 来源：网络整理
导读：话不多说，请看代码： 0SET @Pages_total = @Pages_total + 1ENDENDIF @Order_type = 1BEGINSET @Var_QC = ' (select max'SET @Order_QC = ' order by [' + @Rows_order + '] asc'ENDIF @PageIndex = 1BEGINIF @Rows_condition != ''SET @MainSQL_QC = 'sele
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话不多说，请看代码： 0 SET @Pages_total = @Pages_total + 1 END END IF @Order_type = 1 BEGIN SET @Var_QC = '<(select min' SET @Order_QC = ' order by [' + @Rows_order + '] desc' END ELSE BEGIN SET @Var_QC = '>(select max' SET @Order_QC = ' order by [' + @Rows_order + '] asc' END IF @PageIndex = 1 BEGIN IF @Rows_condition != '' SET @MainSQL_QC = 'select top ' + str(@PageSizes) + ' ' +@Rows_target + ' from [' + @Table_name + '] where ' + @Rows_condition + ' ' + @Order_QC ELSE SET @MainSQL_QC = 'select top ' + str(@PageSizes) + ' ' +@Rows_target + ' from [' + @Table_name + '] ' + @Order_QC END ELSE BEGIN IF @Rows_condition != '' SET @MainSQL_QC = 'select top ' + str(@PageSizes) + ' ' +@Rows_target + ' from [' + @Table_name + '] where [' + @Rows_order + ']' + @Var_QC + '([' + @Rows_order + ']) from (select top ' + str((@PageIndex - 1) *@PageSizes) + ' [' + @Rows_order + '] from [' + @Table_name + '] where ' + @Rows_condition + ' ' + @Order_QC + ') as Tmep_QC) and ' + @Rows_condition + ' ' + @Order_QC ELSE SET @MainSQL_QC = 'select top ' + str(@PageSizes) + ' ' +@Rows_target + ' from [' + @Table_name + '] where [' + @Rows_order + ']' + @Var_QC + '([' + @Rows_order + ']) from (select top ' + str((@PageIndex - 1) *@PageSizes) + ' [' + @Rows_order + '] from [' + @Table_name + ']' + @Order_QC + ') as Tmep_QC)' + @Order_QC END EXEC (@MainSQL_QC)调用：execute pagination_basic 'UserDetail','*','','id','1','5','' 主要是末尾的语句，拆分下来便是这样： select top 每页数 列名 from [表名] where [排序字段名] < --1 倒序输出若列 小于之前页数的最小值 (select min ( [排序字段名] )from --2 获得一个指定列名中的最小值并输出 (select top (当前页-1)*每页数 [排序字段名] from [表名] where [条件] [排序类型]) --3 选择之前页数总数据倒序输出 as Tmep_QC)--4 建立一个名为Tmep_QC的临时表--2 获得一个指定列名中的最小值并输出 and [条件] [排序类型]--1 倒序输出若列 小于之前页数的最小值 以上就是本文的全部内容，希望本文的内容对大家的学习或者工作能带来一定的帮助，同时也希望多多支持编程之家！ （编辑：李大同） 【声明】本站内容均来自网络，其相关言论仅代表作者个人观点，不代表本站立场。若无意侵犯到您的权利，请及时与联系站长删除相关内容! |