如何在SQL Server中有效地获取上一行和下一行的值
发布时间:2020-12-12 08:51:00 所属栏目:MsSql教程 来源:网络整理
导读:说我有这些行, InstrumentID 547698708 InstrumentID不是自动生成的列. 假如我在程序中传递参数为698,我应该将之前的值设为547,将下一个值设为708.如何在SQL中有效地执行此操作? 我有这个程序,但效率不高(而且不正确). Alter PROCEDURE GetNextAndPreviousIn
说我有这些行, InstrumentID 547 698 708 InstrumentID不是自动生成的列. 假如我在程序中传递参数为698,我应该将之前的值设为547,将下一个值设为708.如何在SQL中有效地执行此操作? 我有这个程序,但效率不高(而且不正确). Alter PROCEDURE GetNextAndPreviousInsturmentID ( @InstrumentID varchar(14),@PreviousInstrumentID varchar(14) OUT,@NextInstrumentID varchar(14) OUT ) AS BEGIN Declare @RowNum int = 0 Select @RowNum = ROW_NUMBER() Over (Order by Cast(@InstrumentID as decimal(18))) From Documents Where InstrumentID = @InstrumentID ;With normal As ( Select ROW_NUMBER() Over (Order by Cast(@InstrumentID as decimal(18))) as RowNum,Cast(InstrumentID as decimal(18)) as InstrumentID From Documents ) Select @PreviousInstrumentID = InstrumentID From normal Where RowNum = @RowNum - 1 Select @NextInstrumentID = InstrumentID From normal Where RowNum = @RowNum + 1 END GO 解决方法试试这个:Alter PROCEDURE GetNextAndPreviousInsturmentID ( @InstrumentID varchar(14),@NextInstrumentID varchar(14) OUT ) AS BEGIN Declare @Ids TABLE(Id varchar(14)) ;With normal As ( --Numerate our rows Select ROW_NUMBER() Over (Order by Cast(Documents.InstrumentID as decimal(18)) as RowNumber,Documents.InstrumentID From Documents ) --Insert three rows from our table with our id and previos/next id INSERT INTO @Ids(Id) SELECT TOP(3) normal.InstrumentID FROM normal WHERE RowNumber >= ( SELECT RowNumber - 1 FROM normal WHERE normal.InstrumentID = @InstrumentID ) ORDER BY normal.RowNumber --select next and previos ids SELECT @PreviousInstrumentID = Min(CAST(Id as decimal(18))),@NextInstrumentID = MAX(CAST(Id as decimal(18))) FROM @Ids END GO 在MS SQL 2012中,我们有新的窗口函数,如FIRST_VALUE和LAST_VALUE,遗憾的是在sql 2008中缺少这些函数. (编辑:李大同) 【声明】本站内容均来自网络,其相关言论仅代表作者个人观点,不代表本站立场。若无意侵犯到您的权利,请及时与联系站长删除相关内容! |