sql – 根据另一列重置运行总计
发布时间:2020-12-12 08:47:58 所属栏目:MsSql教程 来源:网络整理
导读:我试图计算运行总计.但是当累积和大于另一个列值时,它应该重置 create table #reset_runn_total(id int identity(1,1),val int,reset_val int)insert into #reset_runn_totalvalues (1,10),(8,12),(6,14),(5,13),(3,11),(9,8),(10,12) 样本数据 +----+-----+-
我试图计算运行总计.但是当累积和大于另一个列值时,它应该重置
create table #reset_runn_total ( id int identity(1,1),val int,reset_val int ) insert into #reset_runn_total values (1,10),(8,12),(6,14),(5,13),(3,11),(9,8),(10,12) 样本数据 +----+-----+-----------+ | id | val | reset_val | +----+-----+-----------+ | 1 | 1 | 10 | | 2 | 8 | 12 | | 3 | 6 | 14 | | 4 | 5 | 10 | | 5 | 6 | 13 | | 6 | 3 | 11 | | 7 | 9 | 8 | | 8 | 10 | 12 | +----+-----+-----------+ 预期结果 +----+-----+-----------------+-------------+ | id | val | reset_val | Running_tot | +----+-----+-----------------+-------------+ | 1 | 1 | 10 | 1 | | 2 | 8 | 12 | 9 | --1+8 | 3 | 6 | 14 | 15 | --1+8+6 -- greater than reset val | 4 | 5 | 10 | 5 | --reset | 5 | 6 | 13 | 11 | --5+6 | 6 | 3 | 11 | 14 | --5+6+3 -- greater than reset val | 7 | 9 | 8 | 9 | --reset -- greater than reset val | 8 | 10 | 12 | 10 | --reset +----+-----+-----------------+-------------+ 查询: ;WITH cte AS (SELECT id,val,reset_val,val AS running_total FROM #reset_runn_total WHERE id = 1 UNION ALL SELECT r.*,CASE WHEN lag(c.running_total + r.val) over(order by r.id) > lag(r.reset_val) over(order by r.id) THEN r.reset_val ELSE c.running_total + r.val END FROM cte c JOIN #reset_runn_total r ON r.id = c.id + 1) SELECT * FROM cte 明显滞后不会得到以前的价值观呢? 解决方法尝试标记上一行WITH cte AS (SELECT id,val AS running_total,CASE WHEN val > reset_val THEN 1 ELSE 0 END as flag FROM #reset_runn_total WHERE id = 1 UNION ALL SELECT r.*,CASE c.flag WHEN 1 then r.val ELSE c.running_total + r.val END,CASE WHEN CASE c.flag WHEN 1 then r.val ELSE c.running_total + r.val END > r.reset_val THEN 1 ELSE 0 END FROM cte c JOIN #reset_runn_total r ON r.id = c.id + 1) SELECT * FROM cte (编辑:李大同) 【声明】本站内容均来自网络,其相关言论仅代表作者个人观点,不代表本站立场。若无意侵犯到您的权利,请及时与联系站长删除相关内容! |