SQL Server查询查找从城市A到城市B的所有路由与转移

任务：将航空路线存储在SQL Server表写入查询中,将查找从A城市到B城市的所有路线,无需转移,即可进行一次或两次转移.例如你有路线：

| From         | To
----------------------
Los Angeles     London   
Los Angeles     New York
New York        London
Los Angeles     Seattle
Seattle         Paris
Paris           London

你需要找到从洛杉矶到伦敦的所有路线.结果应该是这样的

Route
------------------------
Los Angeles->London
Los Angeles->New York->London
Los Angeles->Seattle->Paris->London

我的解决方案是这样的

select [From] + '->' + [To] as [Route] from Routes where [From] = 'Los Angeles' and [To] = 'London'
union 
select r1.[From] + '->' + r1.[To] + '->' + r2.[To] as [Route] from Routes as r1 
join Routes as r2 on r1.[To] = r2.[From]
where r1.[From] = 'Los Angeles' and r2.[To] = 'London'
union 
select r1.[From] + '->' + r1.[To] + '->' + r2.[To] + '->' + r3.[To] as [Route] from Routes as r1 
join Routes as r2 on r1.[To] = r2.[From]
join Routes as r3 on r2.[To] = r3.[From]
where r1.[From] = 'Los Angeles' and r3.[To] = 'London'

工作但看起来不是很好,如果我们需要找到3,4,5或更多的转移路线,我们需要添加更多复杂选择的新工会.

对于这个特定的例子,这是很好的,因为人们对于超过2次转机的航班不感兴趣.但一般来说,我认为这个查询可以看起来更好.也许有人可以用更一般的查询来解决这个任务.谢谢.

解决方法

with RoutesCTE as
(
    select CAST([From] + '->' + [To] as nvarchar(max)) as [Route],0 as TransfersCount,[From],[To]
    from Routes

    union all

    select r.[Route] + '->' + r1.[To],TransfersCount + 1,r.[From],r1.[To]
    from RoutesCTE r
        join Routes r1
            on r.[To] = r1.[From]
                and r1.[To] <> r.[From] 
                  and PATINDEX('%'+r1.[To]+'%',r.[Route]) = 0
)
select [Route]
from RoutesCTE 
where [From] = 'Los Angeles'
    and [To] = 'London'
    and TransfersCount <= 2

所以,这里你有一个SQL Server的一般解决方案,你可以通过传递计数过滤它们.

（编辑：李大同）

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