SQL Pivot可以进行以下查询吗?
假设我有以下表格:
create table student( id number not null,name varchar2(80),primary key(id) ); create table class( id number not null,subject varchar2(80),primary key(id) ); create table class_meeting( id number not null,class_id number not null,meeting_sequence number,primary key(id),foreign key(class_id) references class(id) ); create table meeting_attendance( id number not null,student_id number not null,meeting_id number not null,present number not null,foreign key(student_id) references student(id),foreign key(meeting_id) references class_meeting(id),constraint meeting_attendance_uq unique(student_id,meeting_id),constraint present_ck check(present in(0,1)) ); 我想要查询每个类,其中有一个学生名称列,每个class_meeting为此类的一个列,每个类会议单元格将显示当前属性,如果学生出席该会议,该属性应为1如果学生缺席那次会议则为0.这是excel的图片供参考: 是否有可能做出类似的顶级报告? select * from( select s.name,m.present from student s,meeting_attendance m where s.id = m.student_id ) pivot( present for class_meeting in ( select a.meeting_sequence from class_meeting a,class b where b.id = a.class_id ) ) 不过我确信它已经过时了.甚至可以使用一个查询来执行此操作,还是应该使用pl sql htp和htf包来创建html表? 相当缺乏经验的oracle开发人员,所以任何帮助都非常感谢. 解决方法花了一段时间才回答,但我不得不写下这一切并测试它!我使用的数据: begin insert into student(id,name) values (1,'Tom'); insert into student(id,name) values (2,'Odysseas'); insert into class(id,subject) values (1,'Programming'); insert into class(id,subject) values (2,'Databases'); insert into class_meeting (id,class_id,meeting_sequence) values (1,1,10); insert into class_meeting (id,meeting_sequence) values (2,20); insert into class_meeting (id,meeting_sequence) values (3,2,meeting_sequence) values (4,20); insert into meeting_attendance (id,student_id,meeting_id,present) values (1,1); -- Tom was at meeting 10 about programming insert into meeting_attendance (id,present) values (2,1); -- Tom was at meeting 20 about programming insert into meeting_attendance (id,present) values (3,3,0); -- Tom was NOT at meeting 10 about databases insert into meeting_attendance (id,present) values (4,4,0); -- Tom was NOT at meeting 20 about databases insert into meeting_attendance (id,present) values (5,0); -- Odysseas was NOT at meeting 10 about programming insert into meeting_attendance (id,present) values (6,1); -- Odysseas was at meeting 20 about programming insert into meeting_attendance (id,present) values (7,0); -- Odysseas was NOT at meeting 10 about databases insert into meeting_attendance (id,present) values (8,1); -- Odysseas was at meeting 20 about databases end; PIVOT,就像现在一样,不允许以简单的方式使用动态数量的列.它只允许使用XML关键字,从而生成xmltype列. 那怎么样? 动态SQL > https://asktom.oracle.com/pls/asktom/f?p=100:11:0::::P11_QUESTION_ID:4471013000346257238 经典报告可以将函数体返回sql语句作为返回.交互式报告不能.就目前而言,IR是不可能的,因为它太依赖于元数据. 例如,在经典报表区域源中使用这些查询/ plsql: 静态枢轴 select * from ( select s.name as student_name,m.present present,cm.meeting_sequence||'-'|| c.subject meeting from student s join meeting_attendance m on s.id = m.student_id join class_meeting cm on cm.id = m.meeting_id join class c on c.id = cm.class_id ) pivot ( max(present) for meeting in ('10-Databases' as "10-DB",'20-Databases' as "20-DB",'10-Programming' as "10-PRM",'20-Programming' as "20-PRM") ); -- Results STUDENT_NAME '10-Databases' 20-DB 10-PRM 20-PRM Tom 0 0 1 1 Odysseas 0 1 0 1 函数体返回语句 DECLARE l_pivot_cols VARCHAR2(4000); l_pivot_qry VARCHAR2(4000); BEGIN SELECT ''''||listagg(cm.meeting_sequence||'-'||c.subject,''',''') within group(order by 1)||'''' INTO l_pivot_cols FROM class_meeting cm JOIN "CLASS" c ON c.id = cm.class_id; l_pivot_qry := 'select * from ( ' || 'select s.name as student_name,cm.meeting_sequence||''-''||c.subject meeting ' || 'from student s ' || 'join meeting_attendance m ' || 'on s.id = m.student_id ' || 'join class_meeting cm ' || 'on cm.id = m.meeting_id ' || 'join class c ' || 'on c.id = cm.class_id ' || ') ' || 'pivot ( max(present) for meeting in ('||l_pivot_cols||') )' ; RETURN l_pivot_qry; END; 但请注意区域来源中的设置. >使用特定于查询的列名称和验证查询 这是标准设置.它将解析您的查询,然后将查询中找到的列存储在报告元数据中.如果继续使用上面的plsql代码创建报告,您可以看到apex已解析查询并分配了正确的列.这种方法的错误在于元数据是静态的.每次运行报表时都不会刷新报表的元数据. begin insert into class(id,subject) values (3,'Watch YouTube'); insert into class_meeting (id,meeting_sequence) values (5,10); insert into meeting_attendance (id,present) values (10,5,1); -- Tom was at meeting 10 about watching youtube end; 在不编辑报告的情况下运行页面!编辑和保存将重新生成元数据,这显然不是一种可行的方法.无论如何,数据都会发生变化,您无法每次都进入并保存报告元数据. --cleanup begin delete from class where id = 3; delete from class_meeting where id = 5; delete from meeting_attendance where id = 10; end; >使用通用列名称(仅在运行时解析查询) 将源设置为此类型将允许您使用更动态的方法.通过将报告的设置更改为此类型的解析,apex将在其元数据中生成一定数量的列,而不直接与实际查询关联.只有列有’COL1′,’COL2′,’COL3′,…… begin insert into class(id,1); -- Tom was at meeting 10 about watching youtube end; 运行报告.工作良好. DECLARE l_return VARCHAR2(400); BEGIN SELECT listagg(cm.meeting_sequence||'-'||c.subject,':') within group(order by 1) INTO l_return FROM class_meeting cm JOIN "CLASS" c ON c.id = cm.class_id; RETURN l_return; END; 第三方解决方案 > https://asktom.oracle.com/pls/apex/f?p=100:11:0::::P11_QUESTION_ID:4843682300346852395#5394721000346803830 使用XML 我自己之前选择使用XML关键字.我使用pivot来确保我有所有行和列的值,然后使用XMLTABLE再次读出它,然后创建一个XMLTYPE列,将其序列化为CLOB. DECLARE l_return CLOB; BEGIN -- Subqueries: -- SRC -- source data query -- SRC_PIVOT -- pivoted source data with XML clause to allow variable columns. -- Mainly used for convenience because pivot fills in 'gaps' in the data. -- an example would be that 'Odysseas' does not have a relevant record for the 'Watch Youtube' class -- PIVOT_HTML -- Pulls the data from the pivot xml into columns again,and collates the data -- together with xmlelments. -- HTML_HEADERS -- Creates a row with just header elements based on the source data -- HTML_SRC -- Creates row elements with the student name and the collated data from pivot_html -- Finally: -- serializes the xmltype column for easier-on-the-eye markup WITH src AS ( SELECT s.name as student_name,cm.meeting_sequence||'-'||c.subject meeting FROM student s JOIN meeting_attendance m ON s.id = m.student_id JOIN class_meeting cm ON cm.id = m.meeting_id JOIN class c ON c.id = cm.class_id ),src_pivot AS ( SELECT student_name,meeting_xml FROM src pivot xml(MAX(NVL(present,0)) AS is_present_max for (meeting) IN (SELECT distinct meeting FROM src) ) ),pivot_html AS ( SELECT student_name,xmlagg( xmlelement("td",xmlattributes('data' as "class"),is_present_max) ORDER BY meeting ) is_present_html FROM src_pivot,xmltable('PivotSet/item' passing meeting_xml COLUMNS "MEETING" VARCHAR2(400) PATH 'column[@name="MEETING"]',"IS_PRESENT_MAX" NUMBER PATH 'column[@name="IS_PRESENT_MAX"]') GROUP BY (student_name) ),html_headers AS ( SELECT xmlelement("tr",xmlelement("th",xmlattributes('header' as "class"),'Student Name'),xmlagg(xmlelement("th",meeting) order by meeting) ) headers FROM (SELECT DISTINCT meeting FROM src) ),html_src as ( SELECT xmlagg( xmlelement("tr",xmlelement("td",student_name),ah.is_present_html ) ) data FROM pivot_html ah ) SELECT xmlserialize( content xmlelement("table",xmlattributes('report-standard' as "class",'0' as "cellpadding",'0' as "cellspacing",'0' as "border"),xmlelement("thead",headers ),xmlelement("tbody",data ) ) AS CLOB INDENT SIZE = 2 ) INTO l_return FROM html_headers,html_src ; htp.prn(l_return); END; 在APEX中:好吧,既然已经构造了HTML,那么它只能是一个PLSQL区域,它调用包函数并使用HTP.PRN打印它. (编辑)在OTN论坛上也有这篇文章在很大程度上做了同样的事情,但没有生成标题等,而是使用顶点功能: PLSQL 或者,你可以选择去好的’plsql路线.您可以从上面的动态sql获取正文,循环它,并通过使用htp.prn调用放出表结构.拿出标题,并推出你想要的任何其他内容.为了获得良好的效果,请在与您正在使用的主题相对应的元素上添加类. (编辑:李大同) 【声明】本站内容均来自网络,其相关言论仅代表作者个人观点,不代表本站立场。若无意侵犯到您的权利,请及时与联系站长删除相关内容! |