SQL Server 计算两个日期相差的工作天数的语句

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代码如下:

 
if exists (select * from dbo.sysobjects where id = object_id(N'[dbo].[f_WorkDay]') and xtype in (N'FN',N'IF',N'TF')) 
drop function [dbo].[f_WorkDay] 
GO 
--计算两个日期相差的工作天数 
CREATE FUNCTION f_WorkDay( 
@dt_begin datetime,--计算的开始日期 
@dt_end datetime --计算的结束日期 
)RETURNS int 
AS 
BEGIN 
declare @i int 
select @i=abs(datediff(dd,@dt_begin,@dt_end)) 
declare @t table(dt datetime) 
if @dt_begin>@dt_end 
insert @t select dateadd(dd,number,@dt_end) from master..spt_values 
where number<=@i and type='P' 
else 
insert @t select dateadd(dd,@dt_begin) from master..spt_values 
where number<=@i and type='P' 
return(select count(*) from @t where (datepart(weekday,dt)+@@datefirst-1)%7 between 1 and 5) 
END 
GO 
select dbo.f_WorkDay('2009-10-10','2009-10-1') 
/* 
----------- 
7 
(1 個資料列受到影響) 
*/ 
if exists (select * from dbo.sysobjects where id = object_id(N'[dbo].[f_WorkDay]') and xtype in (N'FN',--计算的开始日期 
@dt_end datetime --计算的结束日期 
)RETURNS int 
AS 
BEGIN 
DECLARE @workday int,@i int,@bz bit,@dt datetime 
set @workday=0 
IF @dt_begin>@dt_end 
SELECT @bz=1,@dt=@dt_begin,@dt_begin=@dt_end,@dt_end=@dt 
ELSE 
SET @bz=0 
WHILE @dt_begin<=@dt_end 
BEGIN 
SELECT @workday=CASE 
WHEN (@@DATEFIRST+DATEPART(Weekday,@dt_begin)-1)%7 BETWEEN 1 AND 5 
THEN @workday+1 ELSE @workday END,@dt_begin=@dt_begin+1 
END 
RETURN(CASE WHEN @bz=1 THEN -@workday ELSE @workday END) 
END 
GO 
select dbo.f_WorkDay('2009-10-10','2009-10-1') 
/* 
----------- 
-7 
*/ 

（编辑：李大同）

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