tsql – 可以设置T-SQL DATEDIFF函数的周开始吗？

DATEDIFF(week,DateCreated,GETDATE()) = 0

我注意到周日从星期天开始是什么假设.但在我的情况下,我宁愿在星期一设定一周的开始.在T-SQL中有可能吗？

谢谢！

更新：

下面是一个示例,显示DATEDIFF不检查@@DATEFIRST变量,所以我需要另一个解决方案.

SET DATEFIRST 1;

SELECT 
    DateCreated,DATEDIFF(week,CAST('20090725' AS DATETIME)) AS D25,CAST('20090726' AS DATETIME)) AS D26
FROM
(
    SELECT CAST('20090724' AS DATETIME) AS DateCreated
    UNION 
    SELECT CAST('20090725' AS DATETIME) AS DateCreated
) AS T

输出：

DateCreated             D25         D26
----------------------- ----------- -----------
2009-07-24 00:00:00.000 0           1
2009-07-25 00:00:00.000 0           1

(2 row(s) affected)

2009年7月26日是星期天,我想要DATEDIFF在第三列返回0.

解决方法

SET DATEFIRST 1; -- Monday

从http://msdn.microsoft.com/en-us/library/ms181598.aspx

看来dateiff不尊重Datefirst,所以就这样运行它

create table #testDates (id int identity(1,1),dateAdded datetime)
insert into #testDates values ('2009-07-09 15:41:39.510') -- thu
insert into #testDates values ('2009-07-06 15:41:39.510') -- mon
insert into #testDates values ('2009-07-05 15:41:39.510') -- sun
insert into #testDates values ('2009-07-04 15:41:39.510') -- sat

SET DATEFIRST 7 -- Sunday (Default
select * from #testdates where datediff(ww,DATEADD(dd,-@@datefirst,dateadded),getdate())) = 0
SET DATEFIRST 1 -- Monday
select * from #testdates where datediff(ww,getdate())) = 0

被盗从

http://social.msdn.microsoft.com/Forums/en-US/transactsql/thread/8cc3493a-7ae5-4759-ab2a-e7683165320b

（编辑：李大同）

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