sql – Oracle查询以查找字符串中出现的所有charcter
发布时间:2020-12-12 07:44:15 所属栏目:MsSql教程 来源:网络整理
导读:我必须在toad中编写一个Oracle查询来查找字符串中所有出现的字符.例如,如果我在字符串SSSRNNSRSSR中搜索R,它应该返回位置4,8和11. 我是Oracle新手并试过这个. select instr(mtr_ctrl_flags,'R',pos + 1,1) as pos1 from mer_trans_reject where pos in ( sele
我必须在toad中编写一个Oracle查询来查找字符串中所有出现的字符.例如,如果我在字符串SSSRNNSRSSR中搜索R,它应该返回位置4,8和11.
我是Oracle新手并试过这个. select instr(mtr_ctrl_flags,'R',pos + 1,1) as pos1 from mer_trans_reject where pos in ( select instr(mtr_ctrl_flags,1,1) as pos from mer_trans_reject ); 其中mtr_ctrl_flags是列名.我收到错误,表明pos是无效的标识符. 解决方法扩展GolezTrol的答案,您可以使用正则表达式来显着减少您执行的递归查询的数量:select instr('SSSRNNSRSSR',level) from dual connect by level <= regexp_count('SSSRNNSRSSR','R') REGEXP_COUNT()返回模式匹配的次数,在这种情况下是SS在SSSRNNSRSSR中存在的次数.这会将递归级别限制为您需要的确切数字. INSTR()只是在你的字符串中搜索R的索引. level是递归的深度,但在这种情况下,它也是字符串出现的级别,因为我们限制了所需的递归次数. 如果您想要选择的字符串更复杂,那么您可以使用正则表达式ans REGEXP_INSTR()而不是INSTR()但它会更慢(不是太多)并且除非需要,否则它是不必要的. 所要求的简单基准: 两个CONNECT BY解决方案将指示使用REGEXP_COUNT对此大小的字符串快20%. SQL> set timing on SQL> SQL> -- CONNECT BY with REGEX SQL> declare 2 type t__num is table of number index by binary_integer; 3 t_num t__num; 4 begin 5 for i in 1 .. 100000 loop 6 select instr('SSSRNNSRSSR',level) 7 bulk collect into t_num 8 from dual 9 connect by level <= regexp_count('SSSRNNSRSSR','R') 10 ; 11 end loop; 12 end; 13 / PL/SQL procedure successfully completed. Elapsed: 00:00:03.94 SQL> SQL> -- CONNECT BY with filter SQL> declare 2 type t__num is table of number index by binary_integer; 3 t_num t__num; 4 begin 5 for i in 1 .. 100000 loop 6 select pos 7 bulk collect into t_num 8 from ( select substr('SSSRNNSRSSR',level,1) as character 9,level as pos 10 from dual t 11 connect by level <= length('SSSRNNSRSSR') ) 12 where character = 'R' 13 ; 14 end loop; 15 end; 16 / PL/SQL procedure successfully completed. Elapsed: 00:00:04.80 流水线表函数有点慢,但看看它如何在具有大量匹配的大字符串上执行会很有趣. SQL> -- PIPELINED TABLE FUNCTION SQL> declare 2 type t__num is table of number index by binary_integer; 3 t_num t__num; 4 begin 5 for i in 1 .. 100000 loop 6 select * 7 bulk collect into t_num 8 from table(string_indexes('SSSRNNSRSSR','R')) 9 ; 10 end loop; 11 end; 12 / PL/SQL procedure successfully completed. Elapsed: 00:00:06.54 (编辑:李大同) 【声明】本站内容均来自网络,其相关言论仅代表作者个人观点,不代表本站立场。若无意侵犯到您的权利,请及时与联系站长删除相关内容! |