SQL Server每个分类取最新的几条的SQL实现代码

发布时间：2020-12-12 07:41:08 所属栏目：MsSql教程来源：网络整理

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CREATE TABLE table1( [ID] [bigint] IDENTITY(1,1) NOT NULL,[Name] [nvarchar](128) NOT NULL,[class] int not null,[date] datetime not null)class 表示分类编号。分类数不固定，至少有上千种分类
date 表示该条记录被更新的时间
我们现在想获得每个分类最新被更新的5条记录。
解决方案
select id,name,class,date from(select id,date,row_number() over(partition by class order by date desc)as rowindex from table1) awhere rowindex <= 5
create table #temp
(
company varchar(50),
product varchar(50),
inputDate datetime
)
insert into #temp(company,product,inputDate) values('杭州大明有限公司','汽车1','2010-8-1')
insert into #temp(company,'汽车2','汽车3','汽车4','汽车5','2010-7-1')
insert into #temp(company,inputDate) values('北京小科有限公司',inputDate) values('上海有得有限公司',inputDate) values('天津旺旺有限公司','2010-8-1')
select * from #temp
create proc getdata
@num int
as
begin
select top 4 * from
(
select ( select count(*) from #temp where company=a.company and product<=a.product) as 序号,a.company,a.product,a.inputDate
from #temp a
) b
where 序号>=@num
order by 序号,inputDate desc
end
go
getdata 2
/*
结果
1 杭州大明有限公司汽车1 2010-08-01 00:00:00.000
1 北京小科有限公司汽车1 2010-08-01 00:00:00.000
1 上海有得有限公司汽车1 2010-08-01 00:00:00.000
1 天津旺旺有限公司汽车4 2010-08-01 00:00:00.000
2 天津旺旺有限公司汽车5 2010-08-01 00:00:00.000
2 上海有得有限公司汽车2 2010-08-01 00:00:00.000
2 北京小科有限公司汽车2 2010-08-01 00:00:00.000
2 杭州大明有限公司汽车2 2010-08-01 00:00:00.000
3 杭州大明有限公司汽车3 2010-08-01 00:00:00.000
3 北京小科有限公司汽车3 2010-08-01 00:00:00.000
3 上海有得有限公司汽车3 2010-08-01 00:00:00.000
4 北京小科有限公司汽车4 2010-08-01 00:00:00.000
4 北京小科有限公司汽车4 2010-08-01 00:00:00.000
4 上海有得有限公司汽车4 2010-08-01 00:00:00.000
4 杭州大明有限公司汽车4 2010-08-01 00:00:00.000
5 杭州大明有限公司汽车5 2010-07-01 00:00:00.000
*/
--sql2005
create proc getdata2005
@num int
as
begin
select top 4 * from
(
select row_number() over (partition by company order by product ) as 序号,inputDate desc
end
getdata2005 4
select * from #temp
select ( select count(*) from #temp where company+ product<=a.company+a.product) as 序号,a.inputDate
,a.company+a.product as 唯一标志一行
from #temp a
order by company,product

代码如下:

 
Code highlighting produced by Actipro CodeHighlighter (freeware)http://www.CodeHighlighter.com/-->if object_id(N'company') is not null 
drop table company 
go 
create table company 
( 
companyname varchar(2),product varchar(60) 
) 
--公司1 
insert into company 
select 'A','A1' union 
select 'A','A2' union 
select 'A','A3' union 
select 'A','A4' union 
select 'A','A5' union 
select 'A','A6' union 
select 'A','A7' union 
select 'A','A8' union 
select 'A','A9' union 
select 'A','A10' 
--公司2 
insert into company 
select 'B','B1' union 
select 'B','B2' union 
select 'B','B3' union 
select 'B','B4' union 
select 'B','B5' union 
select 'B','B6' union 
select 'B','B7' union 
select 'B','B8' union 
select 'B','B9' union 
select 'B','B10' 
--公司3 
insert into company 
select 'C','C1' union 
select 'C','C2' union 
select 'C','C3' union 
select 'C','C4' union 
select 'C','C5' union 
select 'C','C6' union 
select 'C','C7' union 
select 'C','C8' union 
select 'C','C9' union 
select 'C','C10' 
--公司4 
insert into company 
select 'D','D1' union 
select 'D','D2' union 
select 'D','D3' union 
select 'D','D4' union 
select 'D','D5' union 
select 'D','D6' union 
select 'D','D7' union 
select 'D','D8' union 
select 'D','D9' union 
select 'D','D10' 
--公司5 
insert into company 
select 'E','E1' union 
select 'E','E2' union 
select 'E','E3' union 
select 'E','E4' union 
select 'E','E5' union 
select 'E','E6' union 
select 'E','E7' union 
select 'E','E8' union 
select 'E','E9' union 
select 'E','E10' 
--公司6 
insert into company 
select 'F','F1' union 
select 'F','F2' union 
select 'F','F3' union 
select 'F','F4' union 
select 'F','F5' union 
select 'F','F6' union 
select 'F','F7' union 
select 'F','F8' union 
select 'F','F9' union 
select 'F','F10' 
--公司7 
insert into company 
select 'G','G1' union 
select 'G','G2' union 
select 'G','G3' union 
select 'G','G4' union 
select 'G','G5' union 
select 'G','G6' union 
select 'G','G7' union 
select 'G','G8' union 
select 'G','G9' union 
select 'G','G10' 
--公司8 
insert into company 
select 'H','H1' union 
select 'H','H2' union 
select 'H','H3' union 
select 'H','H4' union 
select 'H','H5' union 
select 'H','H6' union 
select 'H','H7' union 
select 'H','H8' union 
select 'H','H9' union 
select 'H','H10' 
--公司9 
insert into company 
select 'I','I1' union 
select 'I','I2' union 
select 'I','I3' union 
select 'I','I4' union 
select 'I','I5' union 
select 'I','I6' union 
select 'I','I7' union 
select 'I','I8' union 
select 'I','I9' union 
select 'I','I10' 
--公司10 
insert into company 
select 'J','J1' union 
select 'J','J2' union 
select 'J','J3' union 
select 'J','J4' union 
select 'J','J5' union 
select 'J','J6' union 
select 'J','J7' union 
select 'J','J8' union 
select 'J','J9' union 
select 'J','J10' 
IF (select Object_id('Tempdb..#t')) IS NULL 
select identity(int,1,1) as id,* into #t from company 
order by left(product,1),cast(substring(product,2,2) as int) 
if object_id(N'getdata','P') is not null 
drop table getdata 
go 
create proc getdata 
@num1 int --第几页 
as 
begin 
select companyname,product from 
( 
select row_number() over (partition by companyname order by id) as 序号,* 
from #t 
) a 
where 序号=@num1 
order by companyname 
end 
go 
getdata 4 
go 
DROP procedure getdata

（编辑：李大同）

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