sql – 从另一个表中替换select语句中的一行中的多个标记

Ans_code                      Ans_Desc
-------------------------------------------
50000000000000005770       Enter <B><APN></B> and press Ok.       
40000000000000000164       Enter <B><ACCOUNTNAME></B> in connection name.
40000000000000000165       Enter <B><ACCOUNTNAME></B> in <APN>.

等等.

我的tag_mst有这样的值

TAG_CODE                    TAG_NAME          TAG_VALUE
-------------------------------------------------------
100                          <APN>            EXAMPLE.COM
101                          <ACCOUNTNAME>    EXAMPLE

现在我的要求是这个我想选择答案表答案表,替换标签桅杆的值.一个ans_desc中可以有多个标记.

我在想这个方法

>循环answer_dtl的结果从单个记录中获取标记
>循环记录中的多个标记,然后替换
标签
>存储在临时表中,然后打开新的tem表的光标.

这是方法吗？或者有任何简单的方法来做到这一点.

解决方法

SQL> WITH data AS (
  2     SELECT ans_code,Ans_Desc,tag_name,tag_value,3            row_number() OVER (partition BY ans_code ORDER BY t.rowid) no,4            row_number() OVER
  5               (partition BY ans_code ORDER BY t.rowid DESC) is_last
  6        FROM answer_step_dtl a
  7        JOIN tag_mst t ON a.ans_desc LIKE '%' || t.tag_name || '%'
  8  ),n(ans_code,no,is_last,replaced) AS (
  9     SELECT ans_code,no n,10            replace (ans_desc,tag_value) replaced
 11       FROM data
 12      WHERE no = 1
 13     UNION ALL
 14     SELECT d.ans_code,d.no,d.is_last,15            replace (n.replaced,d.tag_name,d.tag_value) replaced
 16       FROM data d
 17       JOIN n ON d.ans_code = n.ans_code
 18        AND d.no = n.no + 1
 19  )
 20  SELECT *
 21    FROM n
 22   WHERE is_last=1;

ANS_CODE             NO IS_LAST REPLACED
-------------------- -- ------- ---------------------------------------
40000000000000000164  1       1 Enter <B>EXAMPLE</B> in connection
50000000000000005770  1       1 Enter <B>EXAMPLE.COM</B> and press Ok.
40000000000000000165  2       1 Enter <B>EXAMPLE</B> in EXAMPLE.COM.

初步答案：

您可以使用PL / SQL函数.即使有多个要替换的标签,以下内容也能正常工作：

CREATE OR REPLACE FUNCTION replacetags(p_desc VARCHAR2)
   RETURN VARCHAR2 IS
   l_result  LONG := p_desc;
   l_tag_pos INTEGER := 1;
   l_tag     tag_mst.tag_name%TYPE;
BEGIN
   LOOP
      l_tag     := regexp_substr(l_result,'<[^<]+>',l_tag_pos);
      l_tag_pos := regexp_instr(l_result,l_tag_pos) + 1;
      EXIT WHEN l_tag IS NULL;
      BEGIN
         SELECT replace(l_result,l_tag,tag_value)
           INTO l_result
           FROM tag_mst
          WHERE tag_name = l_tag;
      EXCEPTION
         WHEN no_data_found THEN
            NULL; -- tag doesn't exist in tag_mst
      END;
   END LOOP;
   RETURN l_result;
END;

SQL> SELECT ans_code,replacetags(ans_desc)
  2    FROM answer_step_dtl;

ANS_CODE              REPLACETAGS(ANS_DESC)
--------------------- ----------------------------------------
50000000000000005770  Enter <B>EXAMPLE.COM</B> and press Ok.
40000000000000000164  Enter <B>EXAMPLE</B> in connection
40000000000000000165  Enter <B>EXAMPLE</B> in EXAMPLE.COM.

（编辑：李大同）

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