oracle―SQL技巧之(一)连续记录查询sql案例测试

发布时间：2020-12-12 07:25:09 所属栏目：MsSql教程来源：网络整理

导读：需求说明：需要查询出某个客户某一年那些天是有连续办理过业务实现SQL如下：创建表：复制代码代码如下: create table test_num (tyear number, tdate date); 测试数据： insert into test_num select 2014,trunc(sysdate)-1 from dual union all sel

需求说明：
需要查询出某个客户某一年那些天是有连续办理过业务

实现SQL如下：
创建表：
复制代码代码如下:
create table test_num
(tyear number,
tdate date);

测试数据：
insert into test_num
select 2014,trunc(sysdate)-1 from dual union all
select 2014,trunc(sysdate)-002 from dual union all
select 2014,trunc(sysdate)-003 from dual union all
select 2014,trunc(sysdate)-004 from dual union all
select 2014,trunc(sysdate)-005 from dual union all
select 2014,trunc(sysdate)-007 from dual union all
select 2014,trunc(sysdate)-008 from dual union all
select 2014,trunc(sysdate)-009 from dual union all
select 2013,trunc(sysdate)-120 from dual union all
select 2013,trunc(sysdate)-121 from dual union all
select 2013,trunc(sysdate)-122 from dual union all
select 2013,trunc(sysdate)-124 from dual union all
select 2013,trunc(sysdate)-125 from dual union all
select 2013,trunc(sysdate)-127 from dual union all
select 2015,trunc(sysdate)-099 from dual union all
select 2015,trunc(sysdate)-100 from dual union all
select 2015,trunc(sysdate)-101 from dual union all
select 2015,trunc(sysdate)-102 from dual union all
select 2015,trunc(sysdate)-104 from dual union all
select 2015,trunc(sysdate)-105 from dual;

写SQL:
复制代码代码如下:
SELECT TYEAR,MIN(TDATE) AS STARTDATE,MAX(TDATE),COUNT(TYEAR) AS ENDNUM
FROM (SELECT A.*,A.TDATE - ROWNUM AS GNUM
FROM (SELECT * FROM TEST_NUM ORDER BY TYEAR,TDATE) A)
GROUP BY TYEAR,GNUM
ORDER BY TYEAR,MIN(TDATE)

（编辑：李大同）

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