SQL选择:如何从有序数据集返回连续值的计数
发布时间:2020-12-12 07:07:33 所属栏目:MsSql教程 来源:网络整理
导读:以下是我在SQL Server 2008数据库中拥有的表的子集. 我试图输出序列号,具有最大连续LID值的LID和实际计数.重要的是要注意,表按最后更新日期值降序排序(此条件很关键).它可以按序列号分组,也可以按序列号升序或降序排序……更高效,更有意义. 这是数据的样子:
以下是我在SQL Server 2008数据库中拥有的表的子集.
我试图输出序列号,具有最大连续LID值的LID和实际计数.重要的是要注意,表按最后更新日期值降序排序(此条件很关键).它可以按序列号分组,也可以按序列号升序或降序排序……更高效,更有意义. 这是数据的样子: [Serial Number] [LID] [Last Updated Date] -------------------------------------- 123456 AAA 2012-09-24 123456 AAA 2012-09-23 123456 AAA 2012-09-22 123456 AAA 2012-09-21 123456 BBB 2012-09-20 123456 BBB 2012-09-19 123456 AAA 2012-09-18 123456 AAA 2012-09-17 123456 AAA 2012-09-16 234567 BBB 2012-09-24 234567 BBB 2012-09-23 234567 AAA 2012-09-22 表的所??需输出是: [Serial Number] [LID] [LID Count] ------------------------------------------- 123456 AAA 4 234567 BBB 2 我很茫然.我试过用过 ROW_NUMBER() OVER(PARTITION BY [Service Tag],[LID] ORDER BY [Last Updated Date] DESC) 但所有这一切都是打破我的降序日期顺序,我最终得到了在日期范围内发生最多的计数和LID. 在此先感谢您提供的任何帮助! 最好的祝福, VP 解决方法看看下面的例子SQL Fiddle Demo DECLARE @Table TABLE( [Serial Number] INT,[LID] VARCHAR(50),[Last Updated Date] DATETIME ) INSERT INTO @Table SELECT 123456,'AAA','2012-09-24' INSERT INTO @Table SELECT 123456,'2012-09-23' INSERT INTO @Table SELECT 123456,'2012-09-22' INSERT INTO @Table SELECT 123456,'2012-09-21' INSERT INTO @Table SELECT 123456,'BBB','2012-09-20' INSERT INTO @Table SELECT 123456,'2012-09-19' INSERT INTO @Table SELECT 123456,'2012-09-18' INSERT INTO @Table SELECT 123456,'2012-09-17' INSERT INTO @Table SELECT 123456,'2012-09-16' INSERT INTO @Table SELECT 234567,'2012-09-24' INSERT INTO @Table SELECT 234567,'2012-09-23' INSERT INTO @Table SELECT 234567,'2012-09-22' ;WITH Vals AS ( SELECT *,ROW_NUMBER() OVER(ORDER BY [Serial Number],[Last Updated Date] DESC) ROWID FROM @Table ),ValsNext AS ( SELECT v.[Serial Number],v.LID,v.[Last Updated Date],v.ROWID,MIN(vn.ROWID) NextRowID FROM Vals v LEFT JOIN Vals vN ON v.[Serial Number] = vn.[Serial Number] AND v.LID != vn.LID AND v.ROWID < vn.ROWID GROUP BY v.[Serial Number],v.ROWID ),ValDiffs AS ( SELECT vn.[Serial Number],vn.LID,vn. NextRowID - vn.ROWID Consecutive FROM ValsNext vn ),Serials AS ( SELECT [Serial Number],MAX(Consecutive) MaxConsecutive FROM ValDiffs GROUP BY [Serial Number] ) SELECT vd.* FROM Serials s INNER JOIN ValDiffs vd ON s.[Serial Number] = vd.[Serial Number] AND s.MaxConsecutive = vd.Consecutive (编辑:李大同) 【声明】本站内容均来自网络,其相关言论仅代表作者个人观点,不代表本站立场。若无意侵犯到您的权利,请及时与联系站长删除相关内容! |