sql – 如何将多个值传递给存储过程中的单个参数
我正在使用SSRS报告和执行存储过程来为我的报告生成数据
DECLARE @return_value int EXEC @return_value = [dbo].[MYREPORT] @ComparePeriod = 'Daily',@OverrideCompareDate = NULL,@PortfolioId = '5,6',@OverrideStartDate = NULL,@NewPositionsOnly = NULL,@SourceID = 13 SELECT 'Return Value' = @return_value GO 在上面,当我通过@PortfolioId =’5,6’时,它给了我错误的输入 我需要投资组合ID 5和6的所有记录也是发送多个值的正确方法吗? 当我执行我的报告时只给出@PortfolioId =’5’它给了我120条记录 因此,当我给@PortfolioId =’5,它应该只给我190条记录,但它给了我更多的记录,我不明白我哪里出错了. 谁能帮助我? 所有代码都太大而无法粘贴,我粘贴相关代码请提示线索. CREATE PROCEDURE [dbo].[GENERATE_REPORT] ( @ComparePeriod VARCHAR(10),@OverrideCompareDate DATETIME,@PortfolioId VARCHAR(50) = '2',--this must be multiple @OverrideStartDate DATETIME = NULL,@NewPositionsOnly BIT = 0,@SourceID INT = NULL ) AS BEGIN SELECT Position.Date,Position.SecurityId,Position.Level1Industry,Position.MoodyFacilityRating,Position.SPFacilityRating,Position.CompositeFacilityRating,Position.SecurityType,Position.FacilityType,Position.Position FROM Fireball_Reporting.dbo.Reporting_DailyNAV_Pricing POSITION WITH (NOLOCK,READUNCOMMITTED) LEFT JOIN Fireball.dbo.AdditionalSecurityPrice ClosingPrice WITH (NOLOCK,READUNCOMMITTED) ON ClosingPrice.SecurityID = Position.PricingSecurityID AND ClosingPrice.Date = Position.Date AND ClosingPrice.SecurityPriceSourceID = @SourceID AND ClosingPrice.PortfolioID IN ( SELECT PARAM FROM Fireball_Reporting.dbo.ParseMultiValuedParameter(@PortfolioId,',') ) 解决方法这不容易做到.无法使NVARCHAR参数采用“多个值”.之前我所做的是 – 正如您已经做的那样 – 将参数值设置为具有逗号分隔值的列表.然后,将此字符串拆分为存储过程中的部分.可以使用字符串函数完成拆分.将每个部件添加到临时表中.伪代码可以是: CREATE TABLE #TempTable (ID INT) WHILE LEN(@PortfolioID) > 0 BEGIN IF NOT <@PortfolioID contains Comma> BEGIN INSERT INTO #TempTable VALUES CAST(@PortfolioID as INT) SET @PortfolioID = '' END ELSE BEGIN INSERT INTO #Temptable VALUES CAST(<Part until next comma> AS INT) SET @PortfolioID = <Everything after the next comma> END END 然后,将您的条件更改为 WHERE PortfolioId IN (SELECT ID FROM #TempTable) 编辑
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