加入收藏 | 设为首页 | 会员中心 | 我要投稿 李大同 (https://www.lidatong.com.cn/)- 科技、建站、经验、云计算、5G、大数据,站长网!
当前位置: 首页 > 站长学院 > MsSql教程 > 正文

sql – Zend如何创建左连接

发布时间:2020-12-12 06:57:47 所属栏目:MsSql教程 来源:网络整理
导读:如何打开此左连接查询: select advertisercontest.*,advertiseraccount.advertiserid,advertiseraccount.companynamefrom advertisercontestleft join advertiseraccount on advertiseraccount.loginid = advertisercontest.loginid where advertisercontest
如何打开此左连接查询:
select advertisercontest.*,advertiseraccount.advertiserid,advertiseraccount.companyname
from advertisercontest
left join advertiseraccount on advertiseraccount.loginid = advertisercontest.loginid 
where advertisercontest.golive is not NULL;

进入Zend的左连接?

解决方法

你可以这样做:
$db = Zend_Db_Table::getDefaultAdapter();

    $select = $db->select();
    $select->from('advertisercontest','*')
            ->joinLeft(
                    'advertiseraccount','advertiseraccount.loginid = advertisercontest.loginid',array('advertiseraccount.advertiserid','advertiseraccount.companyname')
                    )
            ->where('advertisercontest.golive is not NULL');;

    $result = $db->fetchAll($select);

    var_dump($result);

希望没关系.

(编辑:李大同)

【声明】本站内容均来自网络,其相关言论仅代表作者个人观点,不代表本站立场。若无意侵犯到您的权利,请及时与联系站长删除相关内容!

    推荐文章
      热点阅读