sql – 如何在Redshift上查看授权
发布时间:2020-12-12 06:51:38 所属栏目:MsSql教程 来源:网络整理
导读:我想查看红移补助金。 我发现this view for postgres: CREATE OR REPLACE VIEW view_all_grants AS SELECT use.usename as subject,nsp.nspname as namespace,c.relname as item,c.relkind as type,use2.usename as owner,c.relacl,(use2.usename != use.use
我想查看红移补助金。
我发现this view for postgres: CREATE OR REPLACE VIEW view_all_grants AS SELECT use.usename as subject,nsp.nspname as namespace,c.relname as item,c.relkind as type,use2.usename as owner,c.relacl,(use2.usename != use.usename and c.relacl::text !~ ('({|,)' || use.usename || '=')) as public FROM pg_user use cross join pg_class c left join pg_namespace nsp on (c.relnamespace = nsp.oid) left join pg_user use2 on (c.relowner = use2.usesysid) WHERE c.relowner = use.usesysid or c.relacl::text ~ ('({|,)(|' || use.usename || ')=') ORDER BY subject,namespace,item 哪个不起作用,因为relacl的:: text强制转换失败,并带有以下内容: ERROR: cannot cast type aclitem[] to character varying [SQL State=42846] 将查询修改为 CREATE OR REPLACE VIEW view_all_grants AS SELECT use.usename as subject,c.relacl --,)' || use.usename || '=')) as public FROM pg_user use cross join pg_class c left join pg_namespace nsp on (c.relnamespace = nsp.oid) left join pg_user use2 on (c.relowner = use2.usesysid) WHERE c.relowner = use.usesysid -- or c.relacl::text ~ ('({|,item 允许创建视图,但我担心这不会显示所有相关数据。 如何修改视图以使用红移?还是有更好的/替代方法来查看红移上的授权? 更新:Redshift具有HAS_TABLE_PRIVILEGE函数来检查授权。 (见here) 解决方法另一种变化如下:SELECT * FROM ( SELECT schemaname,objectname,usename,HAS_TABLE_PRIVILEGE(usrs.usename,fullobj,'select') AND has_schema_privilege(usrs.usename,schemaname,'usage') AS sel,'insert') AND has_schema_privilege(usrs.usename,'usage') AS ins,'update') AND has_schema_privilege(usrs.usename,'usage') AS upd,'delete') AND has_schema_privilege(usrs.usename,'usage') AS del,'references') AND has_schema_privilege(usrs.usename,'usage') AS ref FROM ( SELECT schemaname,'t' AS obj_type,tablename AS objectname,schemaname + '.' + tablename AS fullobj FROM pg_tables WHERE schemaname not in ('pg_internal') UNION SELECT schemaname,'v' AS obj_type,viewname AS objectname,schemaname + '.' + viewname AS fullobj FROM pg_views WHERE schemaname not in ('pg_internal') ) AS objs,(SELECT * FROM pg_user) AS usrs ORDER BY fullobj ) WHERE (sel = true or ins = true or upd = true or del = true or ref = true) and schemaname='<opt schema>' and usename = '<opt username>'; (编辑:李大同) 【声明】本站内容均来自网络,其相关言论仅代表作者个人观点,不代表本站立场。若无意侵犯到您的权利,请及时与联系站长删除相关内容! |