sql – 使用连接更新Informix表

发布时间：2020-12-12 06:45:50 所属栏目：MsSql教程来源：网络整理

导读：这是Informix更新的正确语法吗？ update table1set table1.code = 100from table1 a,table2 b,table3 cwhere a.key = c.keya.no = b.noa.key = c.keya.code = 10b.tor = 'THE'a.group = 4183a.no in ('1111','1331','1345') 我得到通用的-201’发生语法错误’

这是Informix更新的正确语法吗？

update table1
set table1.code = 100
from table1 a,table2 b,table3 c
where a.key = c.key
a.no = b.no
a.key = c.key
a.code = 10
b.tor = 'THE'
a.group = 4183
a.no in ('1111','1331','1345')

我得到通用的-201’发生语法错误’消息,但我看不出有什么问题.

解决方法

你的语法错误是table1.code

set table1.code = 100

将此更改为

set a.code = 100

完整代码

update table1
set a.code = 100
from table1 a,table3 c
where a.key = c.key
and a.no = b.no
and a.key = c.key
and a.code = 10
and b.tor = 'THE'
and a.group = 4183
and a.no in ('1111','1345')

（编辑：李大同）

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