sql – JPA命名查询匹配IN子句中的元组列表

我有这样一个实体：

class LinkRecord {
  String value;
  int linkType;
  ...
}

我使用(value,linkType)作为复合索引.
对于给定的(v,t)元组列表,我们需要选择DB中的所有记录,以便value = v,linkType = t.

基本上,我想构建此查询：

SELECT * FROM LINK_RECORD WHERE (VALUE,LINK_TYPE) IN (('value1',0),('value2',25),...)

IN子句中的列表作为参数传入的位置.

由于我们正在处理大量数据,因此逐个查询元组是非常不可取的.

在我的存储库中我试过这个：

@Query("select r from LinkRecord r where (r.value,r.linkType) in :keys")
List<LinkRecord> findByValueAndType(@Param("keys")List<List<Object>> keys);

其中keys是一个列表(长度为2的列表).这让我得到ORA_00920：无效的关系运算符.

有没有办法使用命名查询来完成这项工作？或者我是否必须使用本机sql？

谢谢你的帮助.

解决方法

实体……

@Entity
@NamedQueries({
    @NamedQuery(name = "Article.findByIdAndAccessId",query = "SELECT a FROM Article a WHERE a.articlePk IN (:articlePks) ORDER BY a.articlePk.article")
})
@Table(name = "ARTICLE")
public class Article implements Serializable
{
    private static final long serialVersionUID = 1L;

    @EmbeddedId
    private ArticlePk articlePk = new ArticlePk();

    @Column(name = "art_amount")
    private Float amount;

    @Column(name = "art_unit")
    private String unit;

    public Article()
    {
    }

    //more code
}

PK班….

@Embeddable
public class ArticlePk implements Serializable
{
    private static final long serialVersionUID = 1L;

    @Column(name = "art_article")
    private String article;

    @Column(name = "art_acc_identifier")
    private Long identifier;

    public ArticlePk()
    {
    }

    public ArticlePk(String article,Long identifier)
    {
        this.article = article;
        this.identifier = identifier;
    }

    @Override
    public boolean equals(Object other)
    {
        if (this == other)
        {
            return true;
        }
        if (!(other instanceof ArticlePk))
        {
            return false;
        }

        ArticlePk castOther = (ArticlePk)other;
        return this.article.equals(castOther.article) && this.identifier.equals(castOther.identifier);
    }

    @Override
    public int hashCode()
    {
        final int prime = 31;
        int hash = 17;
        hash = hash * prime + this.article.hashCode();
        hash = hash * prime + this.identifier.hashCode();

        return hash;
    }

    //more code
}

调用….

TypedQuery<Article> queryArticle = entityManager.createNamedQuery("Article.findByIdAndAccessId",Article.class);
queryArticle.setParameter("articlePks",articlePks);
List<Article> articles = queryArticle.getResultList();

哪里….

articlePks是List< ArticlePk>.

（编辑：李大同）

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