sql – 按字母顺序查询名称的查询
发布时间:2020-12-12 06:02:02 所属栏目:MsSql教程 来源:网络整理
导读:我使用了LIKE条件,但它要求我在数据库中输入全名来查找名称. if (searchby.equals("Name")){ try { Class.forName("sun.jdbc.odbc.JdbcOdbcDriver"); System.out.println("n Driver loaded"); Connection con=DriverManager.getConnection("jdbc:odbc:wanisa
我使用了LIKE条件,但它要求我在数据库中输入全名来查找名称.
if (searchby.equals("Name")) { try { Class.forName("sun.jdbc.odbc.JdbcOdbcDriver"); System.out.println("n Driver loaded"); Connection con=DriverManager.getConnection("jdbc:odbc:wanisamajDB"); Statement stmt=con.createStatement(); ResultSet rs = stmt.executeQuery("SELECT Name FROM FAMILYcensus WHERE Name LIKE '"+ tfsearch.getText()+"'"); // ResultSet rs = stmt.executeQuery("SELECT Name FROM FAMILYcensus WHERE Name LIKE ); System.out.println("Hi"); rs.next(); String names = rs.getString("NAME"); System.out.println("NAME: " + names ); JOptionPane.showMessageDialog(null,"RECORD FOUND"); tasearch.setText(names); } catch (Exception e) { System.out.println("EXCEPTION " + e); } 解决方法WhiteFang34还说你需要迭代.但是您还需要更改为WHERE子句:"SELECT * FROM FAMILYcensus WHERE Name > '"+ tfsearch.getText()+"' ORDER BY Name ASC LIMIT "+MAXRESULTS; 请注意,限制结果数量是一个好主意. (编辑:李大同) 【声明】本站内容均来自网络,其相关言论仅代表作者个人观点,不代表本站立场。若无意侵犯到您的权利,请及时与联系站长删除相关内容! |