如何在VB.NET代码中触发事件?
发布时间:2020-12-17 00:02:52 所属栏目:大数据 来源:网络整理
导读:我有一个具有开始按钮的表单(允许用户根据需要反复运行进程),并且我想在表单加载时发送btnStart.Click事件,以便进程自动启动. 我有btnStart.Click事件的以下函数,但我如何实际告诉Visual Basic’假装有人点击了按钮并触发此事件’? 我试过非常简单,基本上可
我有一个具有开始按钮的表单(允许用户根据需要反复运行进程),并且我想在表单加载时发送btnStart.Click事件,以便进程自动启动.
我有btnStart.Click事件的以下函数,但我如何实际告诉Visual Basic’假装有人点击了按钮并触发此事件’? 我试过非常简单,基本上可行.但是,Visual Studio给我一个警告变量’sender’在被赋值之前被使用,所以我猜这不是真正的方法: Dim sender As Object btnStart_Click(sender,New EventArgs()) 我也尝试过使用RaiseEvent btnStart.Click,但是会出现以下错误:
码 Imports System.ComponentModel Partial Public Class frmProgress Private bw As BackgroundWorker = New BackgroundWorker Public Sub New() InitializeComponent() ' Set up the BackgroundWorker bw.WorkerReportsProgress = True bw.WorkerSupportsCancellation = True AddHandler bw.DoWork,AddressOf bw_DoWork AddHandler bw.ProgressChanged,AddressOf bw_ProgressChanged AddHandler bw.RunWorkerCompleted,AddressOf bw_RunWorkerCompleted ' Fire the 'btnStart.click' event when the form loads Dim sender As Object btnStart_Click(sender,New EventArgs()) End Sub Private Sub btnStart_Click(sender As Object,e As EventArgs) Handles btnStart.Click If Not bw.IsBusy = True Then ' Enable the 'More >>' button on the form,as there will now be details for users to view Me.btnMore.Enabled = True ' Update the form control settings so that they correctly formatted when the processing starts set_form_on_start() bw.RunWorkerAsync() End If End Sub ' Other functions exist here End Class
您应该将一个按钮作为发送者发送到事件处理程序中:
btnStart_Click(btnStart,New EventArgs()) (编辑:李大同) 【声明】本站内容均来自网络,其相关言论仅代表作者个人观点,不代表本站立场。若无意侵犯到您的权利,请及时与联系站长删除相关内容! |