平时很喜欢玩数独游戏,每天只要信报上有数独游戏,那就不看别的了,专心致志玩一路。
昨天突然想自己编一个软件来算吧,于是就有了这篇文章和一个vb的数独计算器。
下载地址:
http://download.csdn.net/source/1381913
谈思想吧,思想最重要:我用了最最笨的方法,就是每个空位都从1~9挨个填,出了问题再折回来重新填。
所以这样的想法一定要用到递归了,就是不断调用自身来达到目的。
东西简单,所以代码也简单:
我用了81个text来填数:text1(0)~text1(80),存到一个 Mtx(81)的数组中。
而且先写了一个填写检查程序:(目的是检查是否可以在x,y这个位置填入此Num。)
Function Tcheck(arrayc() As Integer,x As Integer,y As Integer,num As Integer) For i = 0 To 8 If Mtx(i,y) = num Then Tcheck = False Exit Function End If If Mtx(x,i) = num Then Tcheck = False Exit Function End If Next i
For i = 0 To 2 For j = 0 To 2 If (arrayc((x/3)*3 + i,(y/3)*3 + j) = num) Then Tcheck = False Exit Function End If Next j Next i Tcheck = True
End Function
Private Function checkexistNum() '检查现有的数据是否存在问题 Dim i As Integer Dim j As Integer Dim temp As Integer
For i = 0 To 8 For j = 0 To 8 If (Mtx(i,j) <> 0) Then temp = Mtx(i,j) Mtx(i,j) = 0 If Tcheck(Mtx,i,j,temp) = False Then checkexistNum = False errorstr = temp Text1(i * 9 + j).SetFocus Exit Function End If Mtx(i,j) = temp End If Next j Next i checkexistNum = True End Function
下面这个程序就是最重要的递归函数了:
Function CalcArray(arrayn() As Integer) Dim k As Integer Dim i As Integer Dim j As Integer
For i = 0 To 8 For j = 0 To 8 If arrayn(i * 9 + j) = 0 Then '原来的值为0才能进行赋值试验 Dim flag As Boolean flag = False For k = 1 To 9 '准备填数 flag = Tcheck(arrayn(),k) If flag = True Then arrayn(i * 9 + j) = k If CalcArray(arrayn) = False Then arrayn(i * 9 + j) = 0 flag = False Else CalcArray= True Exit Function End If End If Next k If flag = False Then CalcArray = False Exit Function End If End If Next j Next i CalcArray = True End Function
ok,最后一步就是主函数了:
Private Sub CalculatorCT_Click()
Dim i,j As Integer
SodoError = 0 t = Timer transfer '这个就是将text1转到Mtx()中去 If SodoError = 1 Then Exit Sub End If
If checkexistNum = False Then MsgBox "现有数据存在问题:" & errorstr Exit Sub End If
If CalcArray(Mtx) = False Then MsgBox "无法解出","龙卷风数独" Else '将资料填回Text1中 For i = 0 To 8 For j = 0 To 8 Text1(j + (i * 9)) = Mtx(i,j) Next j Next i MsgBox "计算完成","龙卷风数独" End If
End Sub
呵呵,简单吧!
发个我做的软件链接:
http://download.csdn.net/source/1381913
完 (编辑:李大同)
【声明】本站内容均来自网络,其相关言论仅代表作者个人观点,不代表本站立场。若无意侵犯到您的权利,请及时与联系站长删除相关内容!
|