常用位操作技巧(Golang)
发布时间:2020-12-16 18:48:21  所属栏目:大数据  来源:网络整理 
            导读:1,判断奇偶 for i := 0; i 100; i++ {if i % 2 == 0 { println(i)}if i 0x1 == 0 { println(i)} } 2,交换两个数 func Swap(a,b *int) {if *a^*b != 0 {temp := *a*a = *b*b = temp}}func Swap(a,b *int) {if *a^*b != 0 {*a = *a + *b*b = *a - *b*a = *a -
                
                
                
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                         1,判断奇偶 for i := 0; i < 100; i++ {
if i % 2 == 0 {
    println(i)
}
if i & 0x1 == 0 {
    println(i)
} 
} 2,交换两个数 func Swap(a,b *int) {
	if *a^*b != 0 {
		temp := *a
		*a = *b
		*b = temp
	}
}
func Swap(a,b *int) {
	if *a^*b != 0 {
		*a = *a + *b
		*b = *a - *b
		*a = *a - *b
	}
}
func Swap(a,b *int) {
	if *a^*b != 0 {
		*a ^= *b
		*b ^= *a
		*a ^= *b
	}
} 
3,交换符号 func ExcangeSymbol(a int) (ret int) {
	ret = ^a + 1
	return
} 
4,求绝对值 func CalcAbs(a int) (ret int) {
    ret = (a ^ a>>31) - a>>31
    return
} 
5,二进制逆序 func ByteReverse(a int) int {
    a = ((a & 0xAAAA) >> 1) | ((a & 0x5555) << 1)
    a = ((a & 0xCCCC) >> 2) | ((a & 0x3333) << 2)
    a = ((a & 0xF0F0) >> 4) | ((a & 0x0F0F) << 4)
    a = ((a & 0xFF00) >> 8) | ((a & 0x00FF) << 8)
    return a
} 
6,求1的个数 func CalcOneNum(a int) int {
    a = ((a & 0xAAAA) >> 1) + (a & 0x5555)
    a = ((a & 0xCCCC) >> 2) + (a & 0x3333)
    a = ((a & 0xF0F0) >> 4) + (a & 0x0F0F)
    a = ((a & 0xFF00) >> 8) + (a & 0x00FF)
    return a
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