Go语言把IP转为int存储.节省空间提高索引速度
发布时间:2020-12-16 18:35:54 所属栏目:大数据 来源:网络整理
导读:package mainimport ("errors""fmt""strconv""strings")type IntIP struct {IP stringIntip int}func main() {var x *IntIP = IntIP{IP: "192.168.1.1"}fmt.Println(x)x.ToIntIp()fmt.Println(*x)}func (self *IntIP) String() string {return self.IP}func
package main import ( "errors" "fmt" "strconv" "strings" ) type IntIP struct { IP string Intip int } func main() { var x *IntIP = &IntIP{IP: "192.168.1.1"} fmt.Println(x) x.ToIntIp() fmt.Println(*x) } func (self *IntIP) String() string { return self.IP } func (self *IntIP) ToIntIp() (int,error) { Intip,err := ConvertToIntIP(self.IP) if err != nil { return 0,err } self.Intip = Intip return Intip,nil } func (self *IntIP) ToString() (string,error) { i4 := self.Intip & 255 i3 := self.Intip >> 8 & 255 i2 := self.Intip >> 16 & 255 i1 := self.Intip >> 24 & 255 if i1 > 255 || i2 > 255 || i3 > 255 || i4 > 255 { return "",errors.New("Isn't a IntIP Type.") } ipstring := fmt.Sprintf("%d.%d.%d.%d",i4,i3,i2,i1) self.IP = ipstring return ipstring,nil } func ConvertToIntIP(ip string) (int,error) { ips := strings.Split(ip,".") E := errors.New("Not A IP.") if len(ips) != 4 { return 0,E } var intIP int for k,v := range ips { i,err := strconv.Atoi(v) if err != nil || i > 255 { return 0,E } intIP = intIP | i<<uint(8*(3-k)) } return intIP,nil } (编辑:李大同) 【声明】本站内容均来自网络,其相关言论仅代表作者个人观点,不代表本站立场。若无意侵犯到您的权利,请及时与联系站长删除相关内容! |