验证 – 如何在Perl 6中定义Ints的Arrayreference的自定义类型?
发布时间:2020-12-16 06:27:42 所属栏目:大数据 来源:网络整理
导读:如何在Perl 6中定义Ints的自定义类型的Ints参考?我试过这个,但它不起作用: subset Array_of_Int of Array where *.all ~~ Int; my $n = My::Class.new( option = 22 3 4 5 );# Type check failed in assignment to $!option; expected My::Class::Array_of
如何在Perl 6中定义Ints的自定义类型的Ints参考?我试过这个,但它不起作用:
subset Array_of_Int of Array where *.all ~~ Int; my $n = My::Class.new( option => < 22 3 4 5 > ); # Type check failed in assignment to $!option; expected My::Class::Array_of_Int but got List in block <unit> at ... 解决方法
在My :: Class中:
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