perl formatting time
发布时间:2020-12-16 00:10:06 所属栏目:大数据 来源:网络整理
导读:Formatting Time ~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~ 方法一: use POSIX qw(strftime);my $timeStr1 = strftime "%Y-%m-%d",localtime;my $timeStr2 = strftime "%Y-%m-%d",localtime(time-86400); (前一天)print "$timeStr
Formatting Time
~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~ 方法一: use POSIX qw(strftime); my $timeStr1 = strftime "%Y-%m-%d",localtime; my $timeStr2 = strftime "%Y-%m-%d",localtime(time-86400); (前一天) print "$timeStr n"; 方法二: #!/usr/bin/perl ($sec,$min,$hour,$day,$mon,$year,$weekday,$yeardate,$savinglightday) = (localtime(time)); $sec = ($sec < 10)? "0$sec":$sec; $min = ($min < 10)? "0$min":$min; $hour = ($hour < 10)? "0$hour":$hour; $day = ($day < 10)? "0$day":$day; $mon = ($mon < 9)? "0".($mon+1):($mon+1); $year += 1900; $today = "$day.$mon.$year|$hour:$min:$sec"; print $today."n"; print time."n"; #如果要输出一天前的日期,将time减去一天的秒数(86400)。 (localtime(time-86400)); #!/usr/bin/perl print &get_time(10)."n"; sub get_time { $interval = $_[0]*60; ($sec,$savinglightday) = (localtime(time + $interval)); $sec = ($sec < 10)? "0$sec":$sec; $min = ($min < 10)? "0$min":$min; $hour = ($hour < 10)? "0$hour":$hour; $day = ($day < 10)? "0$day":$day; $mon = ($mon < 9)? "0".($mon+1):($mon+1); $year += 1900; return "$year-$mon-$day $hour:$min:$sec.00"; } sub getTime(){ (my $sec,my $min,my $hour,my $day,my $mon,my $year,my $weekday,my $yeardate,my $savinglightday) = (localtime(time)); $sec = ($sec < 10)? "0$sec":$sec; $min = ($min < 10)? "0$min":$min; $hour = ($hour < 10)? "0$hour":$hour; $day = ($day < 10)? "0$day":$day; $mon = ($mon < 9)? "0".($mon+1):($mon+1); $year += 1900; my $now = "$year$mon$day $hour:$min:$sec "; return $now; } 方法三: print scalar gmtime ; print scalar localtime (编辑:李大同) 【声明】本站内容均来自网络,其相关言论仅代表作者个人观点,不代表本站立场。若无意侵犯到您的权利,请及时与联系站长删除相关内容! |