perl – 如何在Catalyst应用程序中公开多对多标记样式的关系?
我正在Catalyst中构建一个数据库应用程序,使用jqGrid来完成处理数据显示的混乱工作.除了能够通过“标签”过滤搜索结果外,我几乎所有工作都有效.我有三个表,关系如下:
package MyApp::Schema::Result::Project; ... __PACKAGE__->has_many( "job_flags","MyApp::Schema::Result::ProjectFlag",{ "foreign.project_id" => "self.id" },{ cascade_copy => 0,cascade_delete => 0 },); ... __PACKAGE__->many_to_many(flags => 'project_flags','flag'); 1; 和 package MyApp::Schema::Result::Flag; ... __PACKAGE__->has_many( "project_flags",{ "foreign.flag_id" => "self.id" },); ... __PACKAGE__->many_to_many(projects => 'project_flags','project'); 1; 最后,连接表 package MyApp::Schema::Result::ProjectFlag; ... __PACKAGE__->belongs_to( "flag","MyApp::Schema::Result::Flag",{ id => "flag_id" },{ is_deferrable => 1,on_delete => "CASCADE",on_update => "CASCADE" },); ... __PACKAGE__->belongs_to( "project","MyApp::Schema::Result::Project",{ id => "project_id" },); ... 1; 在我向jqGrid提供JSON数据的控制器中,我使用Catalyst :: TraitFor :: Controller :: jQuery :: jqGrid :: Search将jqGrid生成的请求参数转换为DBIx :: Class样式的查询: my $search_filter = $self->jqGrid_search($c->req->params); my $project_rs = $c->model('DB::Project')->search( $search_filter,{ join => 'project_flags',group_by => 'id',},); 然后传递给jqGrid页面生成器: $project_rs = $self->jqgrid_page($c,$project_rs); 然后我迭代结果集并构建我的jqGrid列. 在HTML方面,我能够构建一个类似的JSON字符串 {"groupOp":"AND","rules":[{"field":"project_flags.flag_id","op":"eq","data":"2"}]} 在这种情况下,显示项目在project_flags中有一行,标志ID为2. 我完全知道我没有正确地做到这一点!我在Catalyst和DBIx :: Class上可以找到的所有文档都表现出类似的想法,但我无法理解如何将它们应用于这种情况(不是我没有尝试过). >我将如何构建“has_flag($flag_id)” – 类型访问器,然后能够在jqGrid的API中使用它们?在我的Catalyst应用程序中它属于哪里? 解决方法
我必须对你诚实,我不完全确定我理解你的问题.看起来你要问的是DBIx :: Class比Catalyst更多 – 后者我知之甚少,前者我每天都在学习更多.考虑到这一点,这是我回答你的问题的最佳尝试.我使用Mojolicious作为MVC,因为这是我最了解的.
首先,我首先创建一个多对多数据库: CREATE TABLE project( id INTEGER PRIMARY KEY,name text ); CREATE TABLE flag( id INTEGER PRIMARY KEY,name text ); CREATE TABLE project_flag( project_id integer not null,flag_id integer not null,FOREIGN KEY(project_id) REFERENCES project(id),FOREIGN KEY(flag_id) REFERENCES flag(id) ); INSERT INTO project (id,name) VALUES (1,'project1'); INSERT INTO project (id,name) VALUES (2,'project2'); INSERT INTO project (id,name) VALUES (3,'project3'); INSERT INTO flag (id,'flag1'); INSERT INTO flag (id,'flag2'); INSERT INTO flag (id,'flag3'); INSERT INTO flag (id,name) VALUES (4,'flag4'); INSERT INTO project_flag (project_id,flag_id) VALUES (1,1); INSERT INTO project_flag (project_id,2); INSERT INTO project_flag (project_id,3); INSERT INTO project_flag (project_id,4); INSERT INTO project_flag (project_id,flag_id) VALUES (2,4); 这是我的Perl(Mojolicious)代码: #!/usr/bin/env perl use Mojolicious::Lite; use Schema; helper db => sub { return Schema->connect('dbi:SQLite:test.db'); }; get '/' => sub { my $self = shift; my $rs = $self->db->resultset('Project')->search( { 'me.name' => 'project3' },{ join => { 'project_flags' => 'flag' },select => ['me.name','flag.name'],as => ['project','flag'] } ); $rs->result_class('DBIx::Class::ResultClass::HashRefInflator'); $self->render( json => [ $rs->all ] ); }; app->start; 这是来自project1的JSON输出(漂亮的打印)(有与之相关的标志): [ { "project":"project1","flag":"flag1" },{ "flag":"flag2","project":"project1" },{ "project":"project1","flag":"flag3" },{ "flag":"flag4","project":"project1" } ] 这里是project3的JSON,与任何标志都没有关系: [ { "project":"project3","flag":null } ] 我把文件放在Github上,所以如果你愿意的话可以check them out. 在你给定的情况下,假设他们在过滤器中输入了“c”这个词,你想要返回标记为“c”的所有内容,然后: my $rs = $self->db->resultset('Tag')->search( { 'me.name' => 'c++' },{ join => { 'project_flags' => 'project' },'project.name'],as => ['tag','project'] } ); $rs->result_class('DBIx::Class::ResultClass::HashRefInflator'); $self->render( json => [ $rs->all ] ); 如果要返回所有列,请使用prefetch而不是join.此外,如果您想支持自动搜索功能,请将搜索更改为search_like,如下所示: my $rs = $self->db->resultset('Tag')->search_like( { 'me.name' => $search_filter.'%' }, 我希望如果我没有回答你的问题,我所提出的至少是朝着正确的方向发展. (编辑:李大同) 【声明】本站内容均来自网络,其相关言论仅代表作者个人观点,不代表本站立场。若无意侵犯到您的权利,请及时与联系站长删除相关内容! |