perl6 – Perl 6在循环遍历列表时显示索引
发布时间:2020-12-15 23:22:52 所属栏目:大数据 来源:网络整理
导读:循环遍历列表(或数组)时,有没有办法知道循环中当前元素的索引? 当然,问题可以通过索引循环来解决: my @aa = 8 .. 12;say "$_t@aa[$_]" for 0 ..^ @aa.elems; 但也许类似下面的内容是可能的(我用.CURRENT_INDEX标记我正在寻找的方法)? my @aa = 8 .. 12;s
循环遍历列表(或数组)时,有没有办法知道循环中当前元素的索引?
当然,问题可以通过索引循环来解决: my @aa = 8 .. 12; say "$_t@aa[$_]" for 0 ..^ @aa.elems; 但也许类似下面的内容是可能的(我用.CURRENT_INDEX标记我正在寻找的方法)? my @aa = 8 .. 12; say $_.CURRENT_INDEXt$_ for @aa; 解决方法
这就是真正发生的事情:
my @aa = 8 .. 12; my iterator = @aa.iterator; while ($_ := iterator.pull-one) !=:= IterationEnd { say $_ } 在这种情况下,迭代器中的值是执行Iterator角色的匿名类. Iterator可能有也可能没有任何方法可以知道它产生了多少值.例如,Iterator for .roll(*)不需要知道它到目前为止产生了多少值,所以它不需要. Iterator可以实现返回其当前索引的方法. my @aa = 8 .. 12; my iterator = class :: does Iterator { has $.index = 0; # declares it as public (creates a method) has @.values; method pull-one () { return IterationEnd unless @!values; ++$!index; # this is not needed in most uses of an Iterator shift @!values; } }.new( values => @aa ); say "{iterator.index}t$_" for Seq.new: iterator; 1 8 2 9 3 10 4 11 5 12 您也可以在更高级别的构造中执行此操作; my @aa = 8 .. 12; my $index = 0; my $seq := gather for @aa { ++$index; take $_ }; say "$indext$_" for $seq; 要使$_. CURRENT-INDEX工作,需要包装结果. class Iterator-Indexer does Iterator { has Iterator $.iterator is required; has $!index = 0; method pull-one () { my current-value = $!iterator.pull-one; # make sure it ends properly return IterationEnd if current-value =:= IterationEnd; # element wrapper class class :: { has $.CURRENT-INDEX; has $.value; # should have a lot more coercion methods to work properly method Str () { $!value } }.new( CURRENT-INDEX => $!index++,value => current-value ) } } multi sub with-index ( Iterator iter ){ Seq.new: Iterator-Indexer.new: iterator => iter; } multi sub with-index ( Iterable iter ){ Seq.new: Iterator-Indexer.new: iterator => iter.iterator; } my @aa = 8 .. 12; say "$_.CURRENT-INDEX()t$_" for with-index @aa.iterator; # note that $_ is an instance of the anonymous wrapper class 再次使用更高级别的构造: my @aa = 8 .. 12; my sequence := @aa.kv.map: -> $index,$_ { # note that this doesn't close over the current value in $index $_ but role { method CURRENT-INDEX () { $index }} } say "$_.CURRENT-INDEX()t$_" for sequence; 我认为你应该只使用.pairs,如果你想要这样的东西. (或使用.kv,但基本上需要使用带有两个参数的for的块形式) my @aa = 8 .. 12; say "$_.key()t$_.value()" for @aa.pairs; (编辑:李大同) 【声明】本站内容均来自网络,其相关言论仅代表作者个人观点,不代表本站立场。若无意侵犯到您的权利,请及时与联系站长删除相关内容! |