perl – 在Moose中创建类属性的最佳方式是什么?
发布时间:2020-12-15 21:33:21 所属栏目:大数据 来源:网络整理
导读:我需要一个在Moose的类属性.现在我在说: #!/usr/bin/perluse 5.010;use strict;use warnings;use MooseX::Declare;class User { has id = (isa = "Str",is = 'ro',builder = '_get_id'); has name = (isa = "Str",is = 'ro'); has balance = (isa = "Num",i
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我需要一个在Moose的类属性.现在我在说:
#!/usr/bin/perl
use 5.010;
use strict;
use warnings;
use MooseX::Declare;
class User {
has id => (isa => "Str",is => 'ro',builder => '_get_id');
has name => (isa => "Str",is => 'ro');
has balance => (isa => "Num",is => 'rw',default => 0);
#FIXME: this should use a database
method _get_id {
state $id = 0; #I would like this to be a class attribute
return $id++;
}
}
my @users;
for my $name (qw/alice bob charlie/) {
push @users,User->new(name => $name);
};
for my $user (@users) {
print $user->name," has an id of ",$user->id,"n";
}
解决方法
我发现MooseX :: ClassAttribute,但它看起来很丑陋.这是最干净的方式吗?
#!/usr/bin/perl
use 5.010;
use strict;
use warnings;
use MooseX::Declare;
class User {
use MooseX::ClassAttribute;
class_has id_pool => (isa => "Int",default => 0);
has id => (isa => "Str",default => 0);
#FIXME: this should use a database
method _get_id {
return __PACKAGE__->id_pool(__PACKAGE__->id_pool+1);
}
}
my @users;
for my $name (qw/alice bob charlie/) {
push @users,"n";
}
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