perl – 在Moose中创建类属性的最佳方式是什么?
发布时间:2020-12-15 21:33:21 所属栏目:大数据 来源:网络整理
导读:我需要一个在Moose的类属性.现在我在说: #!/usr/bin/perluse 5.010;use strict;use warnings;use MooseX::Declare;class User { has id = (isa = "Str",is = 'ro',builder = '_get_id'); has name = (isa = "Str",is = 'ro'); has balance = (isa = "Num",i
我需要一个在Moose的类属性.现在我在说:
#!/usr/bin/perl use 5.010; use strict; use warnings; use MooseX::Declare; class User { has id => (isa => "Str",is => 'ro',builder => '_get_id'); has name => (isa => "Str",is => 'ro'); has balance => (isa => "Num",is => 'rw',default => 0); #FIXME: this should use a database method _get_id { state $id = 0; #I would like this to be a class attribute return $id++; } } my @users; for my $name (qw/alice bob charlie/) { push @users,User->new(name => $name); }; for my $user (@users) { print $user->name," has an id of ",$user->id,"n"; } 解决方法
我发现MooseX :: ClassAttribute,但它看起来很丑陋.这是最干净的方式吗?
#!/usr/bin/perl use 5.010; use strict; use warnings; use MooseX::Declare; class User { use MooseX::ClassAttribute; class_has id_pool => (isa => "Int",default => 0); has id => (isa => "Str",default => 0); #FIXME: this should use a database method _get_id { return __PACKAGE__->id_pool(__PACKAGE__->id_pool+1); } } my @users; for my $name (qw/alice bob charlie/) { push @users,"n"; } (编辑:李大同) 【声明】本站内容均来自网络,其相关言论仅代表作者个人观点,不代表本站立场。若无意侵犯到您的权利,请及时与联系站长删除相关内容! |