TypeError: In order to allow non-dict objects to be serializ

在开发中使用JsonResponse返回数据遇到错误：

TypeError:?In?order?to?allow?non-dict?objects?to?be?serialized?set?the?safe

views.py代码示例

def?userProfile(request):
????posts?=?User.objects.order_by('id')[:10].reverse()
????return?JsonResponse(posts)

JsonResponse源码：

class?JsonResponse(HttpResponse):
????"""
????An?HTTP?response?class?that?consumes?data?to?be?serialized?to?JSON.

????:param?data:?Data?to?be?dumped?into?json.?By?default?only?``dict``?objects
??????are?allowed?to?be?passed?due?to?a?security?flaw?before?EcmaScript?5.?See
??????the?``safe``?parameter?for?more?information.
????:param?encoder:?Should?be?a?json?encoder?class.?Defaults?to
??????``django.core.serializers.json.DjangoJSONEncoder``.
????:param?safe:?Controls?if?only?``dict``?objects?may?be?serialized.?Defaults
??????to?``True``.
????:param?json_dumps_params:?A?dictionary?of?kwargs?passed?to?json.dumps().
????"""

????def?__init__(self,?data,?encoder=DjangoJSONEncoder,?safe=True,?????????????????json_dumps_params=None,?**kwargs):
????????if?safe?and?not?isinstance(data,?dict):
????????????raise?TypeError(
????????????????'In?order?to?allow?non-dict?objects?to?be?serialized?set?the?'
????????????????'safe?parameter?to?False.'
????????????)
????????if?json_dumps_params?is?None:
????????????json_dumps_params?=?{}
????????kwargs.setdefault('content_type',?'application/json')
????????data?=?json.dumps(data,?cls=encoder,?**json_dumps_params)
????????super().__init__(content=data,?**kwargs)

根据源码得知，是因为传入的data参数不是一个字典导致的错误。

解决方法：

def?userProfile(request):
????posts?=?User.objects.order_by('id')[:10].reverse()
????return?JsonResponse(posts,?safe=False)

文档网址：https://docs.djangoproject.com/zh-hans/2.2/_modules/django/http/response/

（编辑：李大同）

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