德尔福 – 连接4:检查获胜者
发布时间:2020-12-15 09:37:54 所属栏目:大数据 来源:网络整理
导读:在Delphi中,我有一个数组形式的Connect 4板表示(7列x 6行): TBoard = Array[1..7,1..6] of SmallInt;Board: TBoard; // instance ob TBoard 每个元素可以有三种不同的状态: 1 =球员1的棋子 0 =空 -1 =玩家2的棋子 现在我需要一个功能来检查是否有赢家或平
在Delphi中,我有一个数组形式的Connect 4板表示(7列x 6行):
TBoard = Array[1..7,1..6] of SmallInt; Board: TBoard; // instance ob TBoard 每个元素可以有三种不同的状态: > 1 =球员1的棋子 现在我需要一个功能来检查是否有赢家或平局: function CheckForWinner(): SmallInt; …其中1是玩家1的胜利,0是平局,-1是玩家2的胜利,“nil”是尚未结束的游戏. 我的草案如下 – 分为两个单一功能: function CheckForWinner(): SmallInt; var playerToCheck: ShortInt; s,z: Byte; draw: Boolean; begin draw := TRUE; for s := 1 to 7 do begin for z := 1 to 6 do begin if Board[s,z] = 0 then draw := FALSE; // if there are empty fields then it is no draw end; end; if draw then begin result := 0; end else begin playerToCheck := Board[lastPieceX,lastPieceY]; // only for last-moving player if searchRow(playerToCheck,+1,lastPieceX,lastPieceY) then // search right/left result := playerToCheck else if searchRow(playerToCheck,lastPieceY) then // search up/down result := playerToCheck else if searchRow(playerToCheck,lastPieceY) then // search right-down/left-up result := playerToCheck else if searchRow(playerToCheck,-1,lastPieceY) then // search right-up/left-down result := playerToCheck; else result := nil; end; end; end; function searchRow(player: SmallInt; sChange,zChange: ShortInt; startS,startZ: Byte): Boolean; var inRow,s,z: SmallInt; begin inRow := 0; s := startS; z := startZ; while (Board[s,z] = player) AND (inRow < 4) AND (s >= 1) AND (s <= 7) AND (z >= 1) AND (z <= 6) do begin s := s+sChange; z := z+zChange; inRow := inRow+1; end; s := startS-sChange; z := startZ-zChange; while (Board[s,z] = player) AND (inRow < 4) AND (s >= 1) AND (s <= 7) AND (z >= 1) AND (z <= 6) do begin s := s-sChange; z := z-zChange; inRow := inRow+1; end; if inRow = 4 then result := TRUE else result := FALSE; end; 您如何看待这种方法?你有更好的(更快/更短)的解决方案吗? 非常感谢你! 解决方法
以与您相同的方式检查获胜者,只需少量代码.
我想你不需要检查所有字段来确定游戏是否完成.当你在游戏中放下一块时,只需增加一个计数器.如果计数器达到42并且还没有赢家,则该游戏是平局. function CheckRow(x,y,xd,yd: Integer): Boolean; var c: Integer; function RowLength(x,yd: Integer): Integer; begin Result := 0; repeat Inc(Result); Inc(x,xd); Inc(y,yd); until not ((x in [1..7]) and (y in [1..6]) and (Board[x,y] = c)); end; begin c := Board[x,y]; Result := 4 <= RowLength(x,yd) + RowLength(x,xd*-1,yd*-1) - 1; end; function CheckForWinner(x,y: Integer): Integer; begin Result := 0; if CheckRow(x,1) or CheckRow(x,1,1) or CheckRow(x,0) or CheckRow(x,-1) then Result := Board[x,y]; end; (编辑:李大同) 【声明】本站内容均来自网络,其相关言论仅代表作者个人观点,不代表本站立场。若无意侵犯到您的权利,请及时与联系站长删除相关内容! |