解决报错:JPA-style positional param was not an integral ord
发布时间:2020-12-15 01:10:41 所属栏目:大数据 来源:网络整理
导读:org.hibernate.QueryException: JPA-style positional param was not an integral ordinal; nested exception is java.lang.IllegalArgumentException: org.hibernate.QueryException: JPA-style positional param was not an integral ordinal ? 在用jpa na
org.hibernate.QueryException: JPA-style positional param was not an integral ordinal; nested exception is java.lang.IllegalArgumentException: org.hibernate.QueryException: JPA-style positional param was not an integral ordinal ? 在用jpa nativequery语句中,用spring junit测试发现报错:JPA-style positional param was not an integral ordinal。。。。。。 经过百度与自己代码调试发现:多是sql之间的空格问题,或者sql拼接问题,还有可能是sql语句后面不能有分号。 (编辑:李大同) 【声明】本站内容均来自网络,其相关言论仅代表作者个人观点,不代表本站立场。若无意侵犯到您的权利,请及时与联系站长删除相关内容! |