Lua – 格式整数
发布时间:2020-12-15 00:23:15 所属栏目:大数据 来源:网络整理
导读:我想格式化一个数字看起来如下“1,234”或“1,234,432”或“123,456,789”,你明白了.我尝试这样做如下; function reformatint(i) local length = string.len(i) for v = 1,math.floor(length/3) do for k = 1,3 do newint = string.sub(mystring,-k*v) end n
我想格式化一个数字看起来如下“1,234”或“1,234,432”或“123,456,789”,你明白了.我尝试这样做如下;
function reformatint(i) local length = string.len(i) for v = 1,math.floor(length/3) do for k = 1,3 do newint = string.sub(mystring,-k*v) end newint = ','..newint end return newint end 正如你所看到我尝试失败,问题是我无法弄清楚我正在运行的程序有什么问题,拒绝向我发回错误. 解决方法
这是一个将负数和小数部分考虑在内的函数:
function format_int(number) local i,j,minus,int,fraction = tostring(number):find('([-]?)(%d+)([.]?%d*)') -- reverse the int-string and append a comma to all blocks of 3 digits int = int:reverse():gsub("(%d%d%d)","%1,") -- reverse the int-string back remove an optional comma and put the -- optional minus and fractional part back return minus .. int:reverse():gsub("^,","") .. fraction end assert(format_int(1234) == '1,234') assert(format_int(1234567) == '1,567') assert(format_int(123456789) == '123,789') assert(format_int(123456789.1234) == '123,789.1234') assert(format_int(-123456789.) == '-123,789') assert(format_int(-123456789.1234) == '-123,789.1234') assert(format_int('-123456789.1234') == '-123,789.1234') print('All tests passed!') (编辑:李大同) 【声明】本站内容均来自网络,其相关言论仅代表作者个人观点,不代表本站立场。若无意侵犯到您的权利,请及时与联系站长删除相关内容! |