LeetCode-150-Evaluate Reverse Polish Notation

算法描述：

Evaluate the value of an arithmetic expression in?Reverse Polish Notation.

Valid operators are?+,?-,?*,?/. Each operand may be an integer or another expression.

Note:

• Division between two integers should truncate toward zero.
• The given RPN expression is always valid. That means the expression would always evaluate to a result and there won‘t?be any?divide?by zero operation.

Example 1:

Input: ["2","1","+","3","*"]
Output: 9
Explanation: ((2 + 1) * 3) = 9

Example 2:

Input: ["4","13","5","/","+"]
Output: 6
Explanation: (4 + (13 / 5)) = 6

Example 3:

Input: ["10","6","9","-11","*","17","+"]
Output: 22
Explanation: 
  ((10 * (6 / ((9 + 3) * -11))) + 17) + 5
= ((10 * (6 / (12 * -11))) + 17) + 5
= ((10 * (6 / -132)) + 17) + 5
= ((10 * 0) + 17) + 5
= (0 + 17) + 5
= 17 + 5
= 22

解题思路：逆波特兰表达式，用栈辅助模拟。

    int evalRPN(vector<string>& tokens) {
        if(tokens.size()==0) return 0;
        stack<int> stk;
        for(auto c : tokens){
            if(c == "+" || c == "-" || c== "*" || c=="/"){
                int right = stk.top();
                stk.pop();
                int left = stk.top();
                stk.pop();
                int ans;
                if(c == "+") ans = left + right;
                if(c == "-") ans = left - right;
                if(c == "*") ans = left * right;
                if(c == "/") ans = left / right;
                stk.push(ans);
            }else{
                stk.push(stoi(c));
            }
        }
        return stk.top();
    }