php – Laravel 5.1从原始数据库(或只是一个数组)创建集合或关联

发布时间：2020-12-14 19:36:53 所属栏目：大数据来源：网络整理

导读：给定下面的表结构,我想返回一个Eloquent集合或者至少将原始DB结果转换为关联数组以便于迭代. 房屋 +----+---------------+| id | building_name |+----+---------------+| 1 | Building 1 || 2 | Building 2 |+----+---------------+ 客房 +----+-----------

给定下面的表结构,我想返回一个Eloquent集合或者至少将原始DB结果转换为关联数组以便于迭代.

房屋

+----+---------------+
| id | building_name |
+----+---------------+
|  1 | Building 1    |
|  2 | Building 2    |
+----+---------------+

客房

+----+-----------+-------------+
| id | room_name | building_id |
+----+-----------+-------------+
|  1 | Room 1    |           1 |
|  2 | Room 2    |           1 |
|  3 | Room 3    |           2 |
+----+-----------+-------------+

maintenancelog

+----+-------------------+---------+---------------------+
| id | maintenance_value | room_id |      created_at     |
+----+-------------------+---------+---------------------+
|  1 | Cleaned           |       1 | 2015-09-10 00:54:59 |
|  2 | Cleaned           |       1 | 2015-09-13 01:55:59 |
|  3 | Cleaned           |       2 | 2015-09-09 02:56:59 |
|  4 | Cleaned           |       2 | 2015-09-14 03:57:59 |
|  5 | Cleaned           |       3 | 2015-09-08 04:58:59 |
|  6 | Cleaned           |       3 | 2015-09-15 05:59:59 |
+----+-------------------+---------+---------------------+

现在使用以下原始数据库查询..

$results = DB::select('
  select b.building_name,r.room_name,x.maxdate FROM buildings b
  join rooms r on r.building_id = b.id
  join (select room_id,max(created_at) as maxdate from maintenancelog group by room_id) x on x.room_id=room.id
  having x.maxdate < DATE_SUB(NOW(),INTERVAL 10 DAY)');

回报

Array
(
    [0] => stdClass Object
        (
            [building_name] => Building 1
            [room_name] => Room 1
            [maxdate] => 2015-09-13 01:55:59
        )

    [1] => stdClass Object
        (
            [building_name] => Building 1
            [room_name] => Room 2
            [maxdate] => 2015-09-14 03:57:59 
        )

    [2] => stdClass Object
        (
            [building_name] => Building 2
            [room_name] => Room 3
            [maxdate] => 2015-09-15 05:59:59
        )

是否有给出数组的Laravel辅助函数,我可以指定键和分组命令吗？有点像,按building_name,room_name分组,以便它返回一个集合或关联数组,其中“buildings”和“rooms”作为键,使迭代更容易？我可以建立一个,但这似乎是一个常见的任务. (我做了搜索)

我正在使用Eloquent并为表格制作模型,但查询对我来说太复杂了,无法弄清楚如何将其转换为Eloquent语句.那么即使有一种方法可以使用现有模型创建集合？

(注意我已经弄清楚如何使用关系和查询范围从维护日志 – >房间 – >建筑物向后工作.但它将建筑物置于关系的最低层,我希望它是第一个)

解决方法

在建筑类：

public function rooms(){
    return $this->hasMany('AppRoom');
}

在室内课程：

public function maintenanceLog(){
    return $this->hasMany('AppMaintenanceLog');
}

在MaintenanceLog类中：

public function scopeLongest($query){ //you can name it as you like ofc.
    return $query->orderBy('created_at','desc')->first();
}

最后你可以使用：

foreach(Building::all() as $building){
    foreach($building->rooms() as $room){
        echo 'building: ' . $building->building_name . ' room: ' . $room->room_name . ' maxdate: ' . $room->maintenanceLog()->longest()->created_at;
    }
}

（编辑：李大同）

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