避免跨不同Groovy脚本共享Java元类

我从Java调用了多个Groovy脚本,它们都包含长久的Groovy对象.

我希望我的Groovy脚本对Java类(大约有100个实例)的Java元类进行一些更改.但是,脚本应该能够进行不同的更改,其中一个脚本中的更改不应该反映在其他脚本中.

问题：Java类的元类在所有脚本之间共享.

这个问题类似于How do I undo meta class changes after executing GroovyShell?,但是在这种情况下,我想要两个脚本同时执行,所以在脚本执行后不可能重置.

示例代码

SameTest.java

public interface SameTest {

    void print();
    void addMyMeta(String name);
    void addJavaMeta(String name);
    void callMyMeta(String name);
    void callJavaMeta(String name);

}

SameSame.java

import groovy.lang.Binding;
import groovy.util.GroovyScriptEngine;

public class SameSame {
    public SameTest launchNew() {
        try {
            GroovyScriptEngine scriptEngine = new GroovyScriptEngine(new String[]{""});
            Binding binding = new Binding();
            binding.setVariable("objJava",this);

            SameTest script = (SameTest) scriptEngine.run("test.groovy",binding);
            return script;
        } catch (Exception | AssertionError e) {
            throw new RuntimeException(e);
        }
    }

    public static void main(String[] args) {
        SameSame obj = new SameSame();
        SameTest a = obj.launchNew();
        SameTest b = obj.launchNew();

        a.addMyMeta("a");
        a.callMyMeta("a");
        try {
            b.callMyMeta("a");
            throw new AssertionError("Should never happen");
        } catch (Exception ex) {
            System.out.println("Exception caught: " + ex);
        }
        a.addJavaMeta("q");
        b.callJavaMeta("q");

        a.print();
        b.print();

    }

}

test.groovy

ExpandoMetaClass.enableGlobally()

class Test implements SameTest {

    SameSame objJava

    void print() {
        println 'My meta class is ' + Test.metaClass
        println 'Java meta     is ' + SameSame.metaClass
    }

    void addMyMeta(String name) {
        println "Adding to Groovy: $this $name"
        this.metaClass."$name" << {
            "$name works!"
        }
    }

    void addJavaMeta(String name) {
        println "Adding to Java: $this $name"
        objJava.metaClass."$name" << {
            "$name works!"
        }
    }

    void callMyMeta(String name) {
        println "Calling Groovy: $this $name..."
        "$name"()
        println "Calling Groovy: $this $name...DONE!"
    }

    void callJavaMeta(String name) {
        println "Calling Java: $this $name..."
        objJava."$name"()
        println "Calling Java: $this $name...DONE!"
    }

}

new Test(objJava: objJava)

产量

Adding to Groovy: Test@7ee955a8 a
Calling Groovy: Test@7ee955a8 a...
Calling Groovy: Test@7ee955a8 a...DONE!
Calling Groovy: Test@4a22f9e2 a...
Exception caught: groovy.lang.MissingMethodException: No signature of method: Test.a() is applicable for argument types: () values: []
Possible solutions: any(),any(groovy.lang.Closure),is(java.lang.Object),wait(),wait(long),each(groovy.lang.Closure)
Adding to Java: Test@7ee955a8 q
Calling Java: Test@4a22f9e2 q...
Calling Java: Test@4a22f9e2 q...DONE!
My meta class is groovy.lang.ExpandoMetaClass@2145b572[class Test]
Java meta     is groovy.lang.ExpandoMetaClass@39529185[class SameSame]
My meta class is groovy.lang.ExpandoMetaClass@72f926e6[class Test]
Java meta     is groovy.lang.ExpandoMetaClass@39529185[class SameSame]

期望的结果

显示有关Java元数据的两行应该是不同的.

这应该崩溃：

a.addJavaMeta("q");
b.callJavaMeta("q");

问题

在不同的GroovyScriptEngine实例中使用不同的MetaClassRegistry有可能吗？

或者有什么其他方式可以产生如上所示的期望结果吗？