如何使用groovy构建器生成数组类型的json?
发布时间:2020-12-14 16:35:00 所属栏目:大数据 来源:网络整理
导读:我们可以通过groovy的json构建器生成一个对象类型的json: def builder = new groovy.json.JsonBuilder()def root = builder.people { person { firstName 'Guillame' lastName 'Laforge' // Named arguments are valid values for objects too address( cit
我们可以通过groovy的json构建器生成一个对象类型的json:
def builder = new groovy.json.JsonBuilder() def root = builder.people { person { firstName 'Guillame' lastName 'Laforge' // Named arguments are valid values for objects too address( city: 'Paris',country: 'France',zip: 12345,) married true // a list of values conferences 'JavaOne','Gr8conf' } } def jsonStr = builder.toString() 我喜欢这种类型的语法,但是如何构建一个数组类型的json? 例如. [ {"code": "111","value":"222"},{"code": "222","value":"444"} ] 我发现一些文档说我们应该使用JsonBuilder()构造函数: def mydata = [ ["code": "111","value":"222"],["code": "222","value":"444"] ] def builder = new groovy.json.JsonBuilder(mydata) def jsonStr = builder.toString() 但是我更喜欢第一种语法.是否可以使用它生成array-type json? 解决方法
你提出的语法看起来不太可能,因为我不相信它是有效的groovy.诸如{“blah”:“foo”}之类的关闭没有任何意义,你会被语法限制所限制.我认为你能够做的最好的是以下内容:
def root = builder.call ( [ { code "111" value "222" },{code "222"; value "444"},//note these are statements within a closure,so ';' separates instead of ',',and no ':' used [code: "333",value:"555"],//map also allowed [1,5,7] //as are nested lists ] ) (编辑:李大同) 【声明】本站内容均来自网络,其相关言论仅代表作者个人观点,不代表本站立场。若无意侵犯到您的权利,请及时与联系站长删除相关内容! |