奇怪的Groovy / Java String比较行为

发布时间：2020-12-14 16:32:11 所属栏目：大数据来源：网络整理

导读：请考虑以下脚本： def a = new HashSet()def str1 = "str1"def str2 = "str2"def b = "$str1-$str2"def c = "str1-str2"println "b: $b"println "c: $c"println "b.equals(c): " + (b.equals(c))println "b == c: " + (b == c)println "b.compareTo(c): " +

请考虑以下脚本：

def a = new HashSet()
def str1 = "str1"
def str2 = "str2"
def b = "$str1-$str2"
def c = "str1-str2"
println "b: $b"
println "c: $c"
println "b.equals(c): " + (b.equals(c))
println "b == c: " + (b == c)
println "b.compareTo(c): " + (b.compareTo(c))

a.add(b)
println "a.contains(c): " + a.contains(c)

使用Groovy 1.8和JDK 1.6.0_14运行时,其输出如下：

b: str1-str2                                                                                                               
c: str1-str2
b.equals(c): false
b == c: true
b.compareTo(c): 0
a.contains(c): false

两个字符串“b”和“c”打印相同的字符序列,但是b.equals(c)是假的.根据JDK 1.6手册,equals()函数应该返回：

Compares this string to the specified object. The result is true if and only if the argument is not null and is a String object that represents the same sequence of characters as this object.

为什么equals()不返回上面记录和演示的值？奇怪的是,compareTo()返回0！

解决方法

问题在 Groovy GString page上得到解答.我需要在GString上调用toString().

（编辑：李大同）

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