Groovy合并两个列表？

发布时间：2020-12-14 16:29:07 所属栏目：大数据来源：网络整理

导读：我有两个清单： listA: [[Name: mr good,note: good,rating:9],[Name: mr bad,note: bad,rating:5]] listB: [[Name: mr good,score:77],score:12]] 我想得到这个 listC:[[Name: mr good,rating:9,rating:5,score:12]] 我怎么能这样做？谢谢. 解决方法收集l

我有两个清单：

listA: 
[[Name: mr good,note: good,rating:9],[Name: mr bad,note: bad,rating:5]] 

listB: 
[[Name: mr good,score:77],score:12]]

我想得到这个

listC:
[[Name: mr good,rating:9,rating:5,score:12]]

我怎么能这样做？

谢谢.

解决方法

收集listA中的所有元素,并在listB中找到elementA equivilient.从listB中删除它,并返回组合元素.

如果我们说你的结构如上,我可能会这样做：

def listC = listA.collect( { elementA ->
    elementB = listB.find { it.Name == elementA.Name }

    // Remove matched element from listB
    listB.remove(elementB)
    // if elementB == null,I use safe reference and elvis-operator
    // This map is the next element in the collect
    [
        Name: it.Name,note: "${it.note} ${elementB?.note :? ''}",// Perhaps combine the two notes?
        rating: it.rating?:0 + elementB?.rating ?: 0,// Perhaps add the ratings?
        score: it.score?:0 + elementB?.score ?: 0 // Perhaps add the scores?
    ] // Combine elementA + elementB anyway you like
}

// Take unmatched elements in listB and add them to listC
listC += listB

（编辑：李大同）

【声明】本站内容均来自网络，其相关言论仅代表作者个人观点，不代表本站立场。若无意侵犯到您的权利，请及时与联系站长删除相关内容!